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01/06/2008 at 12:30PM PST, ID: 23062334

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8.2

how do you populate a dropdown with php?

Asked by RupertA in PHP and Databases, MySQL Server, PHP Scripting Language

Tags: dropdown, populate, query

Hi, I am doing a small one off php page with sql queries to launch some pages from a menu. I was hoping somebody could maybe help me out with a few lines of code for something. To the experienced I would imagine this is fairly easy. Whilst I will tr, I am novice to php/sql and need a help.

I have this menu page as shown in this diagram.

http://www.ruperta.plus.com/menu.gif

I have done this php page so far where I populate the "select your business" dropdown by a simple sql query. That works. It populates three items, Plumb, Parts, Build. I have put the code at the bottom here and uploaded the php file to some webspace (it won't work properly as I have just put it on webspace, not on my php server).

Anyway, what I would like to happen is as follows. Lets say parts is selected from the 'Select your business' dropdown that I have just mentioned above. I would then like the following sql query to be run for 'parts'

// new query
$query = "SELECT Course FROM Brand_Course WHERE ([Contact Centre] = 'Core')";

and the results to appear in a new dropdown underneath (the core dropdown). The [contact centre] should be what has just been selected from the select your business dropdown i.e 'parts'. The result of the query will produce say three items for the new appearing dropdown, so presumably they need to be put in a new array first? i don't know how to do this either. so if somebody could show me the coding from selecting 'parts' on the first dropdown to the new dropdown appearing with the results of the new query I would be very grateful.

Obviously the idea is that as each item on the first dropdown (select your business) is selected the query is run for each business when it is selected and the dropdown below shows the result of the query.

The php file so far is here and I have included the relevant code snippet to this post.

Thank you!

http://www.ruperta.plus.com/course_selection.php

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             <!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN">
<html>
<head>
<title>Course Selection</title>
<meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1">
 
</head>
 
<body>
 
<div style="position:absolute; left:50; top:20">
<img src="training_title.gif">
<div>
 
<div style="position:absolute; left:50; top:133">
<p style="font-family:Verdana; font-size: 10pt">Select your business</p>
</div>
 
 
// this code populates the first drop down, the select your business dropdown
 
<div style="position:absolute; left:180; top:110">
<form method="post" name="Report" id="Report" >
 <select name="Course" id="centre">
            <?php
            //print("including common.php");
            include ('common.php');
            //print("connecting to the db");
            $link = dbConnect();
            //print("connected to: ".$link);
 
            $query = "SELECT DISTINCT business FROM business_tablle";
            $result = mysql_query($query, $link) or die('Query failed: ' . 
 
mysql_error());
 
            print("<Option value =\"Select\">Select</option>");
            while ($row = mysql_fetch_row($result))
            {
                 print("<option value=".$row[0].">".$row[0]."</option>");
            }
 
       ?>
       </select>
 
 
</div>
 
<div style="position:absolute; left:50; top:233">
<p style="font-family:Verdana; font-size: 10pt">Core Courses</p>
</div>
 
</body>
</html>

           
         

20091111-EE-VQP-91 - Hierarchy / EE_QW_2_20070628

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how do you populate a dropdown with php?

Asked by RupertA in PHP and Databases, MySQL Server, PHP Scripting Language

Tags: dropdown, populate, query

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