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7.8

Call MySQL data field into array for drop down selection

Asked by pdheady in PHP and Databases, MySQL Server, PHP Scripting Language

Tags: PHP MySQL

I have a data field that stores drop down items as item1, item2, item3, item4, etc and need the correct code to split into array and perform the drop down. My current code just outputs everything as one drop down selection. How can this be modified to put each item as its own selection.

Here is the html output.

<SELECT NAME="promo" style="background-color: #FCFAB8">
<OPTION VALUE="None, 3 months, 6 months, 12 months, 18 Month no int">None, 3 months, 6 months, 12 months, 18 Month no int
</SELECT>

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<?
$sql = "SELECT 
possible_values
FROM cf_fields
WHERE field_id = 41
";
 
$options="";
 
$query = mysql_query($sql);
 
while ($row=mysql_fetch_array($query)) {
 
    $id=$row["possible_values"];
    $options.="<OPTION VALUE=\"$id\">".$id;
} 
?>
 
 
<SELECT NAME="promo" style="background-color: #FCFAB8">
<?=$options?>
</SELECT>
[+][-]01/11/08 09:20 AM, ID: 20638144Accepted Solution

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About this solution

Zones: PHP and Databases, MySQL Server, PHP Scripting Language
Tags: PHP MySQL
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Solution Provided By: NeoTeq
Participating Experts: 1
Solution Grade: A
 
[+][-]01/11/08 09:30 AM, ID: 20638242Author Comment

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[+][-]11/23/08 11:44 AM, ID: 23025716Administrative Comment

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[+][-]11/27/08 08:07 PM, ID: 23053689Administrative Comment

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