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03.07.2008 at 12:01PM PST, ID: 23223929
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9.3

LEFT JOIN WHERE DATE > NOW Problem

Asked by phper in PHP and Databases, MySQL Server

Tags:

I have a table of venues and a table of shows. The shows table include shows that are older then NOW(). I'm trying to show all the venues in alphbetically order and then show any shows at the venue that are greater than now.

I can LEFT JOIN the two tables. But if I include DATE(show_date) >= NOW() it excludes venues that where show dates have past. So I took out the 'DATE(show_date) >= NOW() ' and added a 'IF > Now' in the page. But because I'm GROUP BY venue name  the query is selecting the first show date, so now no shows are showing.

What I trying to do is:
venues LEFT JOIN shows ON ... WHERE show date >= now. But with all of the venues showing. Here is my current query. Also this query is the one for the page that shows all venues begining with a number. Start Free Trial 
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SELECT venues.vid,venues.VenName,
shows.shband,
shows.shbid,
venues.VenAddress,
venues.VenCity, 
DATE_FORMAT(shows.shdate, '%c/%e %l:%i%p') AS shdatef, 
shows.shdate
FROM venues LEFT Join shows ON venues.vid = shows.shvid WHERE (venues.VenName LIKE '0%' OR venues.VenName LIKE '1%' OR venues.VenName LIKE '2%' OR venues.VenName LIKE '3%' OR venues.VenName LIKE '4%' OR venues.VenName LIKE '5%' OR venues.VenName LIKE '6%' OR venues.VenName LIKE '7%' OR venues.VenName LIKE '8%' OR venues.VenName LIKE '9%')  AND shows.shsame is null GROUP BY venues.VenName ORDER BY venues.VenName, shows.shdate ASC
[+][-]03.07.2008 at 12:59PM PST, ID: 21074086

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About this solution

Zones: PHP and Databases, MySQL Server
Tags: PHP
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Solution Provided By: dsacker
Participating Experts: 1
Solution Grade: A
 
 
 
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