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05.09.2008 at 04:46AM PDT, ID: 23388955
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7.4

checking data in multiple tables.

Zones: PHP and Databases, PHP Scripting Language
I want to check whether the username and password exists in any of the below tables.
table1, table2, table3, .....table8

At present i have started to check like this...

$sql=mysql_query("select * from table1 where username='$username' and pass='$pass'");
if(mysql_num_rows($sql)==0){
         $sql=mysql_query("select * from table2 where username='$username' and pass='$pass'");
         if(mysql_num_rows($sql)==0){
                $sql=mysql_query("select * from table3 where username='$username' and pass='$pass'");
                if(mysql_num_rows($sql)==0){
                      ........................
                      ........................

Is there any best way to do this? I want to check if the entered username and password are valid, so i need to check in all the above mentioned tables.

Any help is appreciated.
Thanks

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Question Stats
Zone: Web Development
Question Asked By: cyberwebservice
Solution Provided By: johnpccd
Participating Experts: 3
Solution Grade: A
Views: 0
Translate:
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05.09.2008 at 04:59AM PDT, ID: 21531875

Rank: Master

MrEne:

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05.09.2008 at 05:06AM PDT, ID: 21531916
zemond:

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05.09.2008 at 07:23AM PDT, ID: 21533110
johnpccd:

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05.09.2008 at 07:24AM PDT, ID: 21533117
johnpccd:

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05.10.2008 at 02:23AM PDT, ID: 21538324
cyberwebservice:

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05.10.2008 at 04:08AM PDT, ID: 21538485
johnpccd:

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05.09.2008 at 04:59AM PDT, ID: 21531875

Rank: Master

MrEne:
you may create a view from table1, table2 and table3 and run your select on that view.

http://dev.mysql.com/doc/refman/5.0/en/create-view.html
 
05.09.2008 at 05:06AM PDT, ID: 21531916
zemond:
Havent actually test this but you could do something like this
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<?php
 
 
$query = "
	SELECT 
		table1.*,
		table2.*,
		table3.*
	FROM
		table1, table2, table3
	WHERE
		table1.username = '$username' AND table1.password = '$password' OR
		table2.username = '$username' AND table2.password = '$password' OR
		table3.username = '$username' AND table3.password = '$password'
	";
		
$result = mysql_query($query);
 
if (mysql_num_rows($result)){
 
	# We good to go
 
}
 
?>
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05.09.2008 at 07:23AM PDT, ID: 21533110
johnpccd:
$n=0;
for($i=1;$i<=8;$i++)
{
$query = " SELECT * FROM `table{$i}` WHERE `username`='{$username}' and `pass`='{$pass}'";
$result_set = mysql_query($query);
$n = $n + mysql_num_rows($result_set);
}

if($n!=0)
{
// user exists
}
 
05.09.2008 at 07:24AM PDT, ID: 21533117
johnpccd:
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$n=0;
for($i=1;$i<=8;$i++)
{
$query = " SELECT * FROM `table{$i}` WHERE `username`='{$username}' and `pass`='{$pass}'";
$result_set = mysql_query($query);
$n = $n + mysql_num_rows($result_set);
}
 
if($n!=0)
{
// user exists
}
Open in New Window
 
05.10.2008 at 02:23AM PDT, ID: 21538324
cyberwebservice:
Thanks for the replies.
@MrEne

How do I create a view combining all the tables?
i just created a view from one table like this:

create view allusers as select * from hotel;

but it gives mysql error. I created it in phpmyAdmin.


@zemond
Your query displays all the entries in the database. For all the rows in table2 and table3, one entry from table1 is displayed. something going wrong.

@johnpccd

I can adopt your method if the tables are really named like the table1, table2 etc...
but the table names are different.

 
05.10.2008 at 04:08AM PDT, ID: 21538485
johnpccd:
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$n=0;
//initialize array
$tables = array();
//push table names
$tables[]='table1';
$tables[]='table2';
$tables[]='table3';
//loop on tables
foreach($tables as $table)
{
$query = " SELECT * FROM `{$table}` WHERE `username`='{$username}' and `pass`='{$pass}'";
$result_set = mysql_query($query);
$n = $n + mysql_num_rows($result_set);
}
 
if($n!=0)
{
// user exists
}
Open in New Window
Accepted Solution
 
 
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