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8.0

unexpected T_EXIT?

Asked by katcarvell in PHP and Databases

Tags: PHP, mySQL, code

I'm not quite sure what they mean here.

Here is my code.

It says line 58.
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<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN"
   "http://www.w3.org/TR/xhtml1-strict.dtd">
<HTML>
 
<head>
 
<LINK href="style4igs.css" rel="stylesheet" type="text/css">
<meta http-equiv="content-type" content="text/html;charset=iso-8859-1">
<title>4IGS.net</title>
<META NAME="keywords" content="gifts, gift, gift certificate, certificate, holiday, christmas, anniversary, price, spa, restaurant, store, bar code, instant, birthday, mothers day, fathers day, thanksgiving, halloween, user interface, log in, instant gift store, businesses">
 
<META NAME="description" content="Instant Gift Certificate: Get gift certificates instantly online!  Perfect for gifts.  Certificates for restaurants, spas, stores, and much more!">
</head>
<body>
 
 
<div>
  <b class="spiffy">
 
  <b class="spiffy1"><b></b></b>
  <b class="spiffy2"><b></b></b>
  <b class="spiffy3"></b>
  <b class="spiffy4"></b>
  <b class="spiffy5"></b></b>
 
  <div class="spiffyfg">
 
<center><font size="4">Log In</font></center>
<h1>&nbsp;</h1>
 
 
<?php
// Connects to your Database
mysql_connect("server_name", "username", "password") or die(mysql_error());
mysql_select_db("database") or die(mysql_error());
 
//Checks if there is a login cookie
$username = $_COOKIE['ID_my_site'];
$pass = $_COOKIE['Key_my_site'];
$check = mysql_query("SELECT * FROM users WHERE username = '$username'")or die(mysql_error());
while($info = mysql_fetch_array( $check ))
{
   if ($pass != $info['password'])
   {
   }
   else
   {
   header("Location: controlpanel.php");
   }
}
 
 
//if the login form is submitted
if (isset($_POST['submit'])) { // if form has been submitted
 
// makes sure they filled it in
if ( (!isset($_POST['username']) || (!isset($_POST['password']) ) 
   die('You did not fill in a required field.');
}
// checks it against the database
 
if (!get_magic_quotes_gpc()) {
$_POST['email'] = addslashes($_POST['email']);
}
$check = mysql_query("SELECT * FROM users WHERE username = '".$_POST['username']."'")or die(mysql_error());
//Gives error if user dosen't exist
$check2 = mysql_num_rows($check);
if ($check2 == 0) {
die('User name not valid.');
}
while($info = mysql_fetch_array( $check ))
{
$_POST['password'] = stripslashes($_POST['password']);
$info['password'] = stripslashes($info['password']);
$_POST['password'] = md5($_POST['password']);
 
//gives error if the password is wrong
if ($_POST['password'] != $info['password']) {
die('Incorrect password, please try again.');
}
else
{
 
// if login is ok then we add a cookie
$_POST['username'] = stripslashes($_POST['username']);
$hour = time() + 3600;
setcookie(ID_my_site, $_POST['username'], $hour);
setcookie(Key_my_site, $_POST['password'], $hour);
 
//then redirect them to the members area
header("Location: controlpanel.php");
exit;
 
// if they are not logged in
?>
<form action="<?php echo !$_SERVER['PHP_SELF']?>" method="post">
<font style="font-family: arial;
color: #ffffff;
font-size: 12px;">Username:
</font>
<br>
<input type="text" name="username" maxlength="40">
<font style="font-family: arial;
color: #ffffff;
font-size: 12px;">Password:
</font>
<br>
<input type="password" name="password" maxlength="50">
 
<input type="submit" name="submit" value="Login" align="right">
 
</form>
<?php
}
 
?>
[+][-]12/29/08 11:10 AM, ID: 23257859Accepted Solution

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About this solution

Zone: PHP and Databases
Tags: PHP, mySQL, code
Sign Up Now!
Solution Provided By: angelIII
Participating Experts: 5
Solution Grade: B
 
[+][-]12/29/08 09:52 AM, ID: 23257259Expert Comment

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[+][-]12/29/08 11:19 AM, ID: 23257935Author Comment

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[+][-]12/30/08 07:47 AM, ID: 23263349Expert Comment

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