Question

php form problem, cant insert new record to table

Asked by: colin0292

hey everyone
im  kinda new to php and mysql and im having trouble inserting new record in to my database table. im not throwing the php code in the same html page. so i have the form in adduser.html then when user add all fields and submit it will go to adduser.php
in adduser.php i was able to check all inputs but cant send them to the database....
any ideas?

### ------HTML FORM--------- ###
<form action="adduser.php" method="post">
First name:<br>
<input type="text" name="fname"><br>
Last name:<br> 
<input type="text" name="lname"><br>
Email:<br> 
<input type="text" name="email"><br>
Password:<br> 
<input type="password" name="password"><br>
School/University:<br>
<input type="text" name="school_name"><br>
City:<br> 
<input type="text" name="city"><br>
State:<br> 
<input type="text" name="state">
 
<INPUT type="submit" value="send"><INPUT type="reset">
 
###----- PHP-----###
 
<?php
include 'config.php';      
include 'opendb.php';
/* Check all form inputs using check_input function */
$fname        = check_input($_POST['fname'], "Enter your first name.");
$lname        = check_input($_POST['lname'], "Enter your last name.");
$password     = check_input($_POST['password'], "Enter your pass.");
$email        = check_input($_POST['email'], "Enter your Email.");
$school_name  = check_input($_POST['school_name'], "Enter your School Name.");
$city         = check_input($_POST['city'], "Enter your City.");
$state        = check_input($_POST['state'], "Enter your State.");
 
 
/* If e-mail is not valid show error message */
if (!preg_match("/([\w\-]+\@[\w\-]+\.[\w\-]+)/", $email))
{
    show_error("E-mail address not valid");
}
else{
$data = "INSERT INTO users VALUES ('NULL', '$fname', '$lname', '$password', '$email', '$school_name', '$city', '$state')";
$query = mysql_query($data);
  if(!$query)
  {
     die(mysql_error());
  }
  else
  {
    
    /* Redirect page */
	/*header('Location: thanks.html');*/
 
 
  } 
echo "<TD valign='top'><br /><center><b>You successed!";
echo "<br>";
}
 
 
 
/* Functions I used to check */
function check_input($data, $problem='')
{
    $data = trim($data);
    $data = stripslashes($data);
    $data = htmlspecialchars($data);
    if ($problem && strlen($data) == 0)
    {
        show_error($problem);
    }
    return $data;
}
 
function show_error($myError)
{
?>
    <html>
    <body>
 
    <b>Please correct the following error:</b><br />
    <?php echo $myError; ?>
 
    </body>
    </html>
<?php
exit();
}
?>

                                  
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Asked On
2009-07-02 at 21:47:56ID24541573
Tags

php

Topic

PHP and Databases

Participating Experts
3
Points
125
Comments
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Answers

 

by: OpalelementPosted on 2009-07-02 at 21:52:35ID: 24769932

Is it returning any mysql error?

 

by: logudotcomPosted on 2009-07-02 at 21:54:10ID: 24769940

Try to print the Insert query and check the syntax.

$data = "INSERT INTO users VALUES ('NULL', '$fname', '$lname', '$password', '$email', '$school_name', '$city', '$state')";
 
echo $data;
 
$query = mysql_query($data);
                                              
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by: colin0292Posted on 2009-07-02 at 22:06:32ID: 24769990

Opalelement it did not return any error

 

by: colin0292Posted on 2009-07-02 at 22:07:12ID: 24769994

logudotcom it didn't echo $data

 

by: OpalelementPosted on 2009-07-02 at 22:09:11ID: 24770004

It would have to echo $data... Are you sure you put it in the right spot?

A test URL would be good:)

 

by: colin0292Posted on 2009-07-02 at 22:14:49ID: 24770031

i think i did put it in the right spot

  } 
echo "<TD valign='top'><br /><center><b>You successed!";
 
echo $data;
 
echo "<br>";
}

                                              
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by: fsze88Posted on 2009-07-02 at 22:17:23ID: 24770043

you can try

$data = "INSERT INTO users (ffield, fname, lname, password, email, school_name, city, state) VALUES ('NULL', '$fname', '$lname', '$password', '$email', '$school_name', '$city', '$state')";

 

by: OpalelementPosted on 2009-07-02 at 22:20:29ID: 24770060

It goes between lines 41 and 42... Between these:

$data = "INSERT INTO users VALUES ('NULL', '$fname', '$lname', '$password', '$email', '$school_name', '$city', '$state')";
$query = mysql_query($data);
                                              
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by: colin0292Posted on 2009-07-02 at 22:22:16ID: 24770071

didn't work fsze88

 

by: fsze88Posted on 2009-07-02 at 22:25:54ID: 24770082

will it caused by missing database link?
$link = mysql_connect('localhost', 'username', 'password');
mysql_query( $data, $link );
??

 

by: OpalelementPosted on 2009-07-02 at 22:27:00ID: 24770084

There would be an error if it wasn't connected to the database. With mysql_query, you don't need to pass the link.

 

by: colin0292Posted on 2009-07-02 at 22:32:20ID: 24770105

Opalelement now it echos $data but still not to database
and about my connection
i have two includes

include 'config.php';      
include 'opendb.php';
see the code below..

============config.php===========
<?php
// This is an example of config.php
$dbhost = 'localhost';
$dbuser = 'colin';
$dbpass = '*****';
$dbname = 'rating';
?>
 
 
============opendb.php==============
<?php
// This is an example opendb.php
$conn = mysql_connect($dbhost, $dbuser, $dbpass) or die('Error connecting to mysql');
mysql_select_db($dbname);
?>

                                              
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by: OpalelementPosted on 2009-07-02 at 22:33:37ID: 24770109

Can you copy and paste the $data that was echoed?

 

by: colin0292Posted on 2009-07-02 at 22:37:07ID: 24770123

Opalelement i think you got this but what should i do with the null thing since the user_id is set to be auto_inc in the table


INSERT INTO users VALUES ('NULL', 'aliiiiiiiiiiiiii', 'rtyu', '123456', 'fghj@dfgh.com', 'dfghjkl;', 'ertyuio', 'cv')Incorrect integer value: 'NULL' for column 'user_id' at row 1

 

by: fsze88Posted on 2009-07-02 at 22:38:26ID: 24770134

you can try omit insert id field

$data = "INSERT INTO users ( fname, lname, password, email, school_name, city, state) VALUES ( '$fname', '$lname', '$password', '$email', '$school_name', '$city', '$state')";

 

by: OpalelementPosted on 2009-07-02 at 22:38:29ID: 24770136

Take null out of single quotes. That makes it so you are passing the word "null", not a null value. So it should be:

$data = "INSERT INTO users VALUES (NULL, '$fname', '$lname', '$password', '$email', '$school_name', '$city', '$state')";
                                              
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