PHP calling one script from another

What in the world do you mean by "The HTML is executed"? I'm acting as a distant echo to nizsmo: please do tell us more.

<? php include('filename.php') ?>

let say..    index.php, header.php, and footer.php

you cannot load  header.html  or footer.html  inside  <? php include('header.html') ?> , just rename the header.html to   header.php  and try again..

i hope that make since..  to make it short and sweet..    if the extension is .html and you are calling it to include("filename.html') it will not work.  just rename the filename.html to filename.php

anyway.. hope this help.. :)  

Hi,

Yes of course. I didn't before because it would be overkill to include all my code. Here is the code relating to what I want to code.

UserSubmitJob.php

[CODE]
include( 'UserJobContactInfo.php' );
var_dump( $_POST );
[CODE]

UserJobContactInfo.php
[CODE]
if( !isset( $_POST['submitContactInfo'] ) )
{
    $selfChanged = "UserJobContactInfo.php";
    $smarty->assign( 'selfChanged', $selfChanged );
    $smarty->display('jobs/UserJobContactInfo.tpl');
}
else
{
      // Do lots of stuff here
      echo "Here";
}
[/CODE]

The include works and [CODE]UserJobContactInfo.php[/CODE] is executed. This script uses smarty to display a HTML form which when completed posts data back to [CODE]UserJobContactInfo.php[/CODE]. The comment do lots of stuff here replaces the processing on that data, which is not important here. The code completes and the echo is printed but execution doesn't return to [CODE]UserSubmitJob.php[/CODE] and the var_dump is never executed. Do I need an exit statement?

Hope this makes sense.

Thanks,

Sean

Hi Sean

Thanks for posting the code, though we have to make sure of one thing, how are you sure that include("UserJobContactInfo.php"); finished executing? Any possibility of it throwing up an error or stopping execution for some reason?

No because it completes fine when I run it independently of the script that includes it. It successfully prints out "here" and the only code after that is closing braces. I want to be able to include the UserJobContactInfo.php so that it displays the HTML form using a smarty template. Goes back to UserJobContactInfo.php to process the data and then access that data through $_POST in the PHP script that included it.

well, to answer the one question, no you don't need exit();. that will definitely stop execution from going back to the calling script. in fact, i believe that and die() should be the only things that stop execution from going back to the calling script.

Of course yes, why is it not returning to the script that includes it?