Question

Don't die() - I'd prefer it if you just fell_over()!

Asked by: mjlindley

Hi,

I've created a class which has a WriteError() method.  WriteError() displays a table with error information.  Once this does its thing, I want it to stop doing anything else.  If I enter "die()" or "exit;" the information isn't displayed on the page.

Is there an intermediate way of getting it to show the information and stop without an all-out die()?


TIA.

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Asked On
2003-07-25 at 06:44:20ID20690313
Tags

die_function

Topic

PHP Scripting Language

Participating Experts
5
Points
125
Comments
13

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Answers

 

by: ThGPosted on 2003-07-25 at 07:18:18ID: 9004461


maybe put that code inside a function() and use a return when you want it to stop processing those section?

 

by: VGRPosted on 2003-07-25 at 07:23:04ID: 9004503

flush() before exitting;

 

by: shmertPosted on 2003-07-25 at 08:48:49ID: 9005474

Install PHP5 and start throwing exceptions!  This is a really great way of doing error handling.  If you have the option of switching to 5, I'd recommend it.

 

by: VGRPosted on 2003-07-25 at 08:55:41ID: 9005541

is it stable ?

 

by: VGRPosted on 2003-07-25 at 08:55:49ID: 9005544

on windows ?

 

by: shmertPosted on 2003-07-25 at 09:01:19ID: 9005590

Been using it (PHP5) for quite a while now, and plan on releasing it on a production system in a few months.  Wrote some OOP DB access code using PHP5 at http://homepage.mac.com/sbarnum/code/alyoop/

 

by: VGRPosted on 2003-07-25 at 09:25:49ID: 9005808

well, I've a hard time being convinced that it's a lot better than PHP4... while PHP4 was clearly more than PHP3+sessions

 

by: blehdaPosted on 2003-07-25 at 20:03:43ID: 9009336

have you tried to call your function directly ? i mean inside of you class
i think that you want to get the error outside of your function... try to call it inside to check out if it works... then outside to see your message

 

by: blehdaPosted on 2003-07-25 at 20:09:21ID: 9009348

$something = new class_name;
print $something->die_function();

class_name = name of your class.
$something = a various variable.
die_funcion = your die funcion inside your class

.. for an outside example if you dont know :)

 

by: Ray_AdamsPosted on 2003-07-28 at 05:38:14ID: 9019155

<?php
class testdie {
 function class_error($text) {
   echo $text;
   die("");
 }
}
echo "before error<br>";

$tr=new testdie;
$tr->class_error("This is error<br>");
echo "after error<br>";
?>

Just tested this simply code and everythiong is ok. Do you use buffering output? But anyway is have to work!
---
<?php
ob_start("ob_gzhandler");

class testdie {
 function class_error($text) {
   echo $text;
   die("");
 }
}
echo "before error<br>";

$tr=new testdie;
$tr->class_error("This is error<br>");
echo "after error<br>";
?>

20120131-EE-VQP-002

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