i have a function which will upload files in a php file !
i want to use that function in multiple files !
problems
1.) when submitting the form to fileA and then calling fileupload function from fileB it will not get the post information.
im not asking u to check my code in validation i just quickly threw the code together in a few minutes but im asking how i can use this functionality by passing the forms information to the function, i could write could to get the info then put it in an array then send it to the function but then why would i even use a function !!!!!!
Answer only if you know
example
fileA.
<?php
//fileA
function fileupload(){
echo $_REQUEST['file1'];
//now copy and load file to server !
}
?>
<?php
//fileB
include fileA.php
if($uploadit=="true"){
fileupload(); //upload the files
}
<form method="post" enctype="multipart/form-da
<input type="file" name="file1">
<input type="hidden" name="uploadit" value="true">
<input type="submit" value="submit">
</form>
?>
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real path not working
heres the code
//here we include it
include (realpath('uploadpage.php'
uploadfiles("4");
--------------------------
//my other file
function uploadfiles($totalfiles){
$maxfilesize=2440000;
for ($c=1; $c < $totalfiles; $c++){
if ($_FILES['file'.$c] < $maxfilesize && $_FILES['file'.$c]['name']
copy($_FILES['file'.$c]['t
$tmp++
}
//even if i echo the $_FILES['file'.$c] into this file it doesnt come up
//if i copy this code to the orginal page it works fine????
hummm i found the problem to be an if statment before the $maxfilesize=2440000;
it states
if($maxfilesize="")
$maxfilesize=2440000;
its sussposed to set a default size if i dont set one, but as u see i forgot my second equals sign and it was assigning a blank size which skipped the code to copy the file
thats such a pain to forget those
1. Security options securing the webspace chosen by admins vary between servers.
2. The web space by default is a public area in the scope of HTTP commands. Private folders are private by default.
2. Something as simple not having an index script present could leave a web folder listable if the server is not configured to stop that.
3. Invoking scripts by name may well run them directly, and if a script can run out of context, the errors may speak volumes about what the vulnerabilities might be.
4. It is a feature of a webserver that any filename without the standard executable extension is downloadable from the webspace.
5. Passwords should NEVER be left in the webspace, or any code that suggests how they are located.
ok i want to assign these points to you ive waited for an answer ????
here better yet i have php files which are outside the web directory and not owned by the users webdirectory owned by root lets say, can i use this technique to hide code, or is it possible for the user to upload a php file to read that file ????
Business Accounts
Answer for Membership
by: ZontarPosted on 2003-12-18 at 23:57:55ID: 9970563
<?php
include( realpath("fileA.php") ); // use either realpath("relative/path/to
if($_POST["uploadit"] == "true")
fileupload();
?>
<form action="<?php echo $_SERVER["PHP_SELF"]; ?>" method="post" enctype="multipart/form-da
<input type="file" name="file1">
<input type="hidden" name="uploadit" value="true">
<input type="submit" value="submit">
</form>
The $_POST and $_FILES variables are superglobals and are available within functions. Use $_FILES instead of $_REQUEST to get uploaded file info; as of PHP 4.3.0, this information is no longer indluded in the $_REQUEST collection.
In fact, I do not recommend using $_REQUEST at all, as this allows people to hack your POST forms using the querystring ($_GET variables). Use $_POST instead.