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04.14.2006 at 09:39AM PDT, ID: 21814215
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7.0

PHP / CAS interface question

Asked by Zeek0 in PHP Scripting Language

Tags: ,

I'm pretty new to PHP, so I'm hoping this is a relatively basic question for anyone who's familiar with common modules and such.

I've built a site that I want to link to a CAS server to authenticate users.  Everything's cool with whisking users to the CAS login page, authenticating them, and getting a service ticket appended as a $_GET variable.  However, I want to validate the ticket and receive their username as part of the server's validation response.  The reponse is in the form of a simple little PHP snippet, called validate.php.  

My problem is that the pre-written code I'm using to run the CAS authentication isn't properly receiving the validate.php data as a variable I can use.  So my question is this:

How do I receive the output validate.php file from the CAS server as an input variable in my code?  The current code uses
$req = new HTTP_Request('{CAS_SERVER}?ticket='.$ticket.'&service='.$this->_service);

where the HTTP_Request() function is from the PEAR package of the same name.  For whatever reason, $req comes back with nothing.  Again, if I type the argument passed to the function (a URL with a query appended to it), I get a correct validate.php in response . . .

Is there a better function/package I should look for to do this?  Like I said, I'm very new to using PHP, so I could well be missing something simple.Start Free Trial
[+][-]04.14.2006 at 01:12PM PDT, ID: 16456788

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[+][-]04.17.2006 at 08:43AM PDT, ID: 16469891

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[+][-]04.17.2006 at 10:09AM PDT, ID: 16470582

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[+][-]04.17.2006 at 10:41AM PDT, ID: 16470847

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[+][-]04.17.2006 at 11:04AM PDT, ID: 16471049

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About this solution

Zone: PHP Scripting Language
Tags: cas, php
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Solution Provided By: theonlygoodisknowledge
Participating Experts: 1
Solution Grade: A
 
 
[+][-]04.17.2006 at 12:46PM PDT, ID: 16471923

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[+][-]04.20.2006 at 09:12AM PDT, ID: 16499738

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