it's correct
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Question
Syntax check
Hello,
Is the syntax correct for the following line of code:
if ($result = mysql_query("SELECT user_name FROM tbl_logged_user WHERE user_name = '$user'"))
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Answers
> the test will return true if some records are returned (eg if the user has been found in the database).
This is wrong, It will test wether the SQL-Statement has been executed successful (no syntax error), but it will not test how many records the resultset will have. So you need to add an additional codition:
if ($result = mysql_query("SELECT user_name FROM tbl_logged_user WHERE user_name = '$user'") && mysql_num_rows($result) > 0)
Is $user $_POST or $_GET or $_COOKIE variable or something else?
Try to use $_POST[user] or $_GET[user] or $_COOKIE[user] accordingly instead of $user if this is a case.
Ideally, the code will be:
if ($result = mysql_query(" SELECT `user_name` FROM `tbl_logged_user` WHERE `user_name` = '$_POST[user]' ")) {
echo "success";
} else {
echo "failure";
}
or
$result = mysql_query(" SELECT `user_name` FROM `tbl_logged_user` WHERE `user_name` = '$_POST[user]' ");
if (mysql_num_rows($result)>0
echo "success, found records";
} else {
echo "failure, no records";
}
make sure that table and field names are correct, you should have field `user_name` in the table `tbl_logged_user`
Good luck.
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by: elfe69Posted on 2007-07-17 at 02:54:42ID: 19503348
Yes, your syntax is correct and the test will return true if some records are returned (eg if the user has been found in the database).