preg_replace("(.*)<code src='(.*)' />(.*)","$2",$file);
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Question
Rewriting ereg_replace to a preg_replace in PHP
How can I rewrite
ereg_replace("(.*)<code src='(.*)' />(.*)", '\\2', $file);
to a preg_replace(...) in PHP?
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Answers
Deresh, with yours I get:
"Warning: preg_replace() [function.preg-replace]: Unknown modifier '<' in /home/phpshare/public_html
And RQuadling, I did need the other parts captured because I just wanted it to return the filename, not the text around it.
So I modifyed RQuadling's source to:
<?php
$file = "I've got some <code src='code.txt' /> here";
$file = preg_replace("`(.*)<code src='(.*?)' />(.*)`sim", "$2", $file);
echo $file;
?>
and it worked.
Thanks!
But in the preg_replace, you don't need even need to get the text around it. You are replacing ....
<code src="code.txt' />
with
code.txt
The other bits are not touched (you don't use $1 or $3), so the capture is not required here.
Its like replacing a substring in a string. You only need to say what you are replacing.
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by: RQuadlingPosted on 2007-08-14 at 03:26:41ID: 19690650
<?php
$file = "I've got some <code src='/code.txt' /> here";
$file = preg_replace("`<code src='(.*?)' />`sim", "$1", $file);
echo $file;
?>
outputs ...
I've got some /code.txt here