This will work for both format input: 2007-11-15 and 11/15/2007, will always output the format 11/15/2007.
Hope this helps.
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Browse All TopicsHave field labeled surgery_date and is either in db as 2007-11-15 or 11/15/2007. It was entered both ways.
I want date as latter option for my output (ie. 11/15/2007)
If I do this for the former result will it keep my latter result intact as 11/15/2007 or will it take 11/15/2007 and make it null because it can't split it. What will happen to the output if I give it a value of 11/15/2007 and run it through the split below? Is there a way to split based on - and /
$surgery_date = $surgery_date;
list($month, $day, $year) = split('[/.-]', $surgery_date);
$surgery_date = "$month/$day/$year";
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by: nizsmoPosted on 2007-12-05 at 13:11:08ID: 20415091
Try:
rgery_date ));
<?php
$surgery_date = "2007-11-15";
$date = date("m/d/Y",strtotime($su
echo $date;
?>