Question

Sending 404 not found from PHP

Asked by: seopti

I'm using an offset of 35 in this mysql query. This way the pagination always shows 35 results (35.html) on the next URL it shows the next 35 (70.html)  results on the next URL the next 35 (105.html) and so on ...

What I would like to do is to force PHP to send a 404 error if a URL is requested which is not 35, not 70 not 105 .... generally which is not defined within my offset.

At the moment if for example a user types in browser 40.html it will show him the result 40.html but it should have shown him 404 because I have not defined 40.html as valid URL in my offset.

Which PHP code can be used to accomplish this?

<?php
include("dbconnect.php");
 
	$bizState = strtoupper($_GET['bizState']);
 
	$offset = $_GET["offset"];
	if(!$offset)
	{
	$offset = 0;
	}
?>		
 
 
 
<?php
  $counter=0;
		$result = mysql_query("SELECT DISTINCT bizCity FROM biz_cars WHERE bizState='$bizState' AND bizLive='1' ORDER BY bizCity ASC LIMIT $offset,35");
 
		while($r=mysql_fetch_array($result))
		{
			$bizCity = $r['bizCity'];
 
			$bizCityLink = str_replace(" ","-",$bizCity);
			$bizCityLink = strtolower($bizCityLink);
 
			$bizStateLink = strtolower($bizState);
			if($counter==0)
                  {
                                        echo "<tr>";
                  }
			
			echo '<td><a href="' . $urlPrefix . 'autcity/' . $bizCityLink . '/' . $bizStateLink . '.html">' . $bizCity . '</a><br></td>';
			
 if($counter==2)
                  {
                        echo "</tr>";
                        $counter = 0;
                        continue;
                  }
                                  $counter++;
            }
            ?>

                                  
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Asked On
2007-12-27 at 12:43:12ID23045784
Tags

PHP

Topics

PHP Scripting Language

,

MySQL Server

Participating Experts
2
Points
500
Comments
5

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Answers

 

by: darron_chapmanPosted on 2007-12-27 at 12:58:07ID: 20537117

something like this... create a pagenotfound.html document and redirect if the offset is not divisible by 35.

<?php
include("dbconnect.php");
 
	$bizState = strtoupper($_GET['bizState']);
 
	$offset = $_GET["offset"];
	if(!$offset)
	{
	$offset = 0;
	}
                elseif ($offset % 35 != 0)
                {
                      header('Location: http://www.yourdomain.com/pagenotfound.html');
                 }
 
?>

                                              
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by: seoptiPosted on 2007-12-27 at 13:10:41ID: 20537214

Thank you for this great solution but I forgot to mention that the last part of the offset is not divisible by 35, so I would server 404 for the last part of offset.

It works this way, let's say they are 469 businesses in a city, it will always divide by 35, so I think using this solution I would get 404 for the last part of offset.

I'm using this small snippet to accomplish the calculation of offset:



<?php
if(!isset($counter))
{
      $counter = '';
}
$numRecords = $numApart;
$totalToDo = $numRecords / 35;
 while ($counter < $totalToDo) {
    $pageNumber = $counter * 35;
        if($pageNumber == 0)
        {
        echo '<a href="'. $urlPrefix . 'autcity/' . $bizCityLink . '/' . $bizStateLink . '.html"><b>' . $pageNumber . '</b></a> | ';
        }
        else
        {
        echo '<a href="'. $urlPrefix . 'autcity/' . $bizCityLink . '/' . $bizStateLink . '-' . $pageNumber . '.html"><b>' . $pageNumber . '</b></a> | ';
        }
$counter = $counter + 1;
}
?>

                                              
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by: darron_chapmanPosted on 2007-12-27 at 13:30:41ID: 20537366

Is it possible to pass the total records to that page and do this?  If the totalrecords is already somewhere on the page, then do this code further down below where totalrecords get defined.  The only caveat of using header is that it needs to be before anything else is written out to the page, or else it won't work.

 

	if(!$offset)
	{
	$offset = 0;
	}
         elseif ($offset=$totalrecords)
         {
         }
         elseif ($offset % 35 != 0)
         {
           header('Location: http://www.yourdomain.com/pagenotfound.html');
         }
                                              
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by: darron_chapmanPosted on 2007-12-27 at 13:32:15ID: 20537385

elseif ($offset=$totalrecords)

should be
elseif ($offset==$totalrecords)

 

by: ed987Posted on 2007-12-27 at 13:33:52ID: 20537398

about sending that 404 status code....

if($offset%35)
{
  header("HTTP/1.0 404 Not Found");
  echo  file_get_contents('404.html'); // optional
  exit;
}

20120131-EE-VQP-002

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