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03.25.2008 at 10:49AM PDT, ID: 23267903
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8.2

why this code is not working..error check

Asked by syedasimmeesaq in PHP Scripting Language, PHP and Databases

I am doing an error check to make sure the users enter something for their email address. I have included the code in the snippet

It catches the error even if I enter something,. So it keeps telling me that I have to provide an email address.
Thanks
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<?
if(isset($_POST['updateinfo'])){
 
if ((!isset($_POST['email'])) || (($_POST['email'])==0))
{
				$err1Start = "<span style='color: green;'><font color='red'>* Please provide your email </font> <br> <br>";
               $err1End   = "</span>";
          }
 
 
if ($err1Start == "")
 
{
 
include_once('rti_con_info.php');		  
$email = $_POST['email'];
 
$sql =
" insert into users (email) values ('".$email."') ";
$runsql = mysql_query($sql) or die (mysql_error());
 
 
}
}
 
?>
 
and the form is
<form id="form1" name="form1" method="post" action="<? $_SERVER['PHP_SELF']; ?>">
<tr>
<td>
     <input type="text" name="email" id="email" onFocus="this.style.background='#FFFFCC'" onBlur="this.style.background='White'"> 
     <?php echo $err1Start ."This will be your Login ID".$err1End; ?></td>
</tr>
<input name="updateinfo" type="submit" value="Insert" >
[+][-]03.25.2008 at 10:50AM PDT, ID: 21204263

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About this solution

Zones: PHP Scripting Language, PHP and Databases
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Solution Provided By: mfsamuel
Participating Experts: 1
Solution Grade: A
 
 
 
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