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03.29.2008 at 10:21AM PDT, ID: 23279613
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File .gif  random select?

Hello all,
There are 500 .gif files in 2 folders folderodd  and foldereven
.gif files are named as  1.gif ,2.gif and ...
the odd numbers are in folderodd and even numbers in foldereven

-I want a script that do these;
Select one file from foldereven randomly and show it,suppose it is 22.gif
then from folderodd select 23.gif(a digit after it in this
example 22.gif and then 23.gif) and show after it.

Thanks in advance
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Question Stats
Zone: Web Development
Question Asked By: MOSTAGHASSI
Solution Provided By: Ray_Paseur
Participating Experts: 2
Solution Grade: A
Views: 0
Translate:
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03.29.2008 at 10:49AM PDT, ID: 21237452

Rank: Guru

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03.29.2008 at 11:34AM PDT, ID: 21237614

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03.29.2008 at 12:32PM PDT, ID: 21237805

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03.29.2008 at 10:49AM PDT, ID: 21237452

Rank: Guru

Mstaghassi, try something like this:

$even_image_nbr = rand(0,498);

if ($even_image_nbr % 2 != 0) { IF WE GOT A RANDOM ODD NUMBER, MAKE IT EVEN
      $even_image_nbr++;
}

$odd_image_nbr      = $even_image_nbr + 1;

$evenlink = "<img src=\"foldereven/$even_image_nbr" . '.gif' . "\">";
$oddlink  = "<img src=\"folderodd/$odd_image_nbr" . '.gif' . "\">";

Good luck, ~Ray
Accepted Solution
 
03.29.2008 at 11:34AM PDT, ID: 21237614
you can use this code
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<?php
	$folderodd = "C:\\folder1";
	$foldereven = "C:\\folder2";
//	$count_odd = 5;
//	$current = 0;
//	$dhnd = opendir($folderodd);
//	$strimgname = readdir($dhnd);
 
	$selected = rand(1, 250) * 2;
	$selected2 = $selected + 1;
	if ($selected2 == 501)
		$selected2 = 1;
//	print "sel: $selected<br />";
//	print "$foldereven\\$selected" . ".gif" . "<br>";
//	print "$folderodd\\$selected2" . ".gif" . "<br>";
?>
	<img src="<?= "$foldereven\\$selected" . ".gif" ?>" >
	<img src="<?= "$folderodd\\$selected2" . ".gif" ?>" >
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03.29.2008 at 12:32PM PDT, ID: 21237805
Ray_Paseur,thanks, it works,thanks also for amilan.
 
 
20080236-EE-VQP-29 / EE_QW_2_20070628