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08.14.2008 at 12:53PM PDT, ID: 23649481
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9.3

Variable Not Passing into Function

Asked by cstormer in PHP Scripting Language

Tags:

In the below code I have a ('$url') which isn't happening... when the function runs it activates this...

http://www.domain.com/$url instead of the $url variableStart Free Trial 
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function remove_worker($worker_id,$part_number)
	{
		global $connect;
		$objResponse = new xajaxResponse();
		$delete="DELETE FROM sfc_current_work WHERE fk_part_number='".$part_number."' AND fk_worker_id=".$worker_id;
		if (!$result = mysql_query($delete , $connect))
		{
			echo $delete;
			echo mysql_error();
			exit;
		}
		$objResponse->addRedirect('$url');
		return $objResponse->getXML();
	}
[+][-]08.14.2008 at 12:57PM PDT, ID: 22233715

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[+][-]08.14.2008 at 01:11PM PDT, ID: 22233822

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About this solution

Zone: PHP Scripting Language
Tags: php, javascript
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Solution Provided By: FreakTrap
Participating Experts: 2
Solution Grade: A
 
 
 
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