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09.26.2008 at 08:22AM PDT, ID: 23766348
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9.1

PHP loop with array only getting last value

Asked by dougfosterNYC in PHP Scripting Language

Tags:

I am new to PHP/MySQL, but a db programmer (SQL Server, VB).  

This should be simple code, and don't see where I'm going wrong.  I am using a graph object, getting some data through a series of queries, and using an array (LOVE PHP for arrays) to loop around the queries.  The adding array to the graph object is from the documentation and isn't the problem. I did this manually and it works, so the loop isn't working properly.

I am only getting the last result.  If I take out the last one, the previous one works fine, so all the queries work fine.  It has to be something simple I'm missing in the fornext loop.

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// include library and create graph object
	include("phpgraphlib.php"); 
	$graph=new PHPGraphLib(400,300);
 
	// do query to get data
	$link1 = @mysql_connect("localhost","earthdev_esadmin","e@rth07gr33n")
					or die("Could not connect to MySQL Server!");
	@mysql_select_db("earthdev_eswave2") or die("Could not select database");
	
	$querys = array("Composition" => "select count(*) as theCount from q16verbs where question='".$_GET['question']."' and response >='10' and response <='19'",
		"Production" => "select count(*) as theCount from q16verbs where question='".$_GET['question']."' and response >='20' and response <='29'",
		"Packaging" => "select count(*) as theCount from q16verbs where question='".$_GET['question']."' and response >='30' and response <='39'",
		"Distribution" => "select count(*) as theCount from q16verbs where question='".$_GET['question']."' and response >='40' and response <='49'",
		"Consumption" => "select count(*) as theCount from q16verbs where question='".$_GET['question']."' and response >='50' and response <='59'",
		"Disposal" => "select count(*) as theCount from q16verbs where question='".$_GET['question']."' and response >='60' and response <='69'");
 
 
	$dataArray=array();
	foreach($querys as $category => $query) 
	{
		$result = mysql_query($query);
	
		if($result)
		{
			while($row = mysql_fetch_assoc($result))
			{	
					$count=$row["theCount"];
								//ADD TO ARRAY
					$dataArray['$category']=$count;
					
			}
		}
	}
 
 
 
	// ---------------------- bar graph
	// first create the graph object with data
 
	$graph->addData($dataArray);
	$graph->setTitle("Product Lifecycle Counts");
	$graph->setGradient("lime", "green");	
	$graph->setBarOutlineColor("black");
	$graph->createGraph();
 
	mysql_close($link1);
[+][-]09.26.2008 at 08:25AM PDT, ID: 22580502

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About this solution

Zone: PHP Scripting Language
Tags: PHP
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Solution Provided By: hielo
Participating Experts: 1
Solution Grade: A
 
 
[+][-]09.26.2008 at 08:45AM PDT, ID: 22580718

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[+][-]09.26.2008 at 09:01AM PDT, ID: 22580873

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[+][-]09.26.2008 at 09:15AM PDT, ID: 22581018

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[+][-]09.26.2008 at 09:47AM PDT, ID: 22581363

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[+][-]09.26.2008 at 10:00AM PDT, ID: 22581488

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[+][-]09.26.2008 at 05:48PM PDT, ID: 22585073

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