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10.04.2008 at 04:52PM PDT, ID: 23787949
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9.9

Pagination and Displaying records problem with mysql_fetch_row and mysql_fetch_array

Asked by Simon336697 in PHP Scripting Language

Hi everyone i hope you are all great.
Guys i have a bugging problem that i would really appreciate your help.
I have a situation where I cannot get both to display records and get pagination working together.
I can get them working independently of each other, which is pretty useless, but i cannot get them working together in the same file.
I have attached in the snippet 3 files:

1)  display_records_only.php   // only contains the display records code...which works
2)  pagination_code_only.php   // only contains the pagination code....which works.
3)  both_pagination_and_records.php // contains both 1) and 2) above, which errors.

In the above, when i run both_pagination_and_records.php, Im getting the following error:

Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource in C:\wamp\www\archive\lab\ee\002\both_pagination_and_records.php on line 135

Line 135 on my pc at home for this page is the following..

$rows=mysql_fetch_array($result);

This is line 301 in the code snippet.

The pagination component seems to work, but I cannot get any records to be displayed, due to this error i think.

Im not sure if it is because im using mysql_fetch_row to get a count of the number of rows in my query, and then a mysql_fetch_array later to display the results.

I would really love your help guys on this one, as at the moment, its pretty useless having pagination working if i cannot display the results.

As i said, both 1) and 2) above actually work independently, but when i combine the code for both into file: both_pagination_and_records.php, it keels over with that error message stated above.

Any help appreciated.





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==================================== pagination_code_only.php
 
<head>
<link rel="stylesheet" media="all" type="text/css" href="css/tasks.css" />
<link rel="stylesheet" media="all" type="text/css" href="css/main_page_styles.css" />
<script src="js/sorttable.js" type="text/javascript"></script>
<script src="js/showhide_div.js" type="text/javascript"></script>
<?php
include ("connectiondb.php");
$tbl_tasks="currenttasks_ctk";
$tbl_projects="projects_pro";
 
?>
</head>
 
<body>
<center><h3>Tasks Database</h3></center>
 
 
<?php
 
/* xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx
Pagination Section:
xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx */
 
/*******************************************************************************
1: Get the required page number:
*******************************************************************************/
 
if (isset($_GET['pageno'])) {
	$pageno = $_GET['pageno'];	
} else {
	$pageno = 1;
}
echo "The current page number is: " . $pageno . "<br>";
 
/*******************************************************************************
2: Identify how many database rows are available:
This code will count how many rows will satisfy the current query.
*******************************************************************************/
 
$query="SELECT count(*) FROM `$tbl_tasks`, `$tbl_projects` where fk_id_pro_ctk = id_pro order by id_ctk asc";
$result = mysql_query($query);
$query_data = mysql_fetch_row($result);
$numrows = $query_data[0];
echo "The number of rows is: " . $numrows;
 
/*******************************************************************************
3: Calculate the number of the $lastpage:
This code uses the values in $rows_per_page (that you specify you want to show)
and $numofrows in order to identify the number of the last page.
*******************************************************************************/
 
$rows_per_page = 15;
$lastpage = ceil($numrows/$rows_per_page);
echo "The value of the last page in this case will be: " . $lastpage . "<br>";
 
/*******************************************************************************
4: Ensure that $pageno is within range:
This code checks that the value of $pageno is an integer between 1 and $lastpage
*******************************************************************************/
 
$pageno = (int)$pageno;
if ($pageno > $lastpage) {
	$pageno = $lastpage;
}
if ($pageno < 1) {
	$pageno = 1;
}
 
/*******************************************************************************
5: Construct LIMIT clause eg. How many rows to view for each page. eg. 10
This code will construct the LIMIT clause for the sql SELECT statement.
*******************************************************************************/
 
$limit = 'LIMIT' . ($pageno - 1) * $rows_per_page . ',' . $rows_per_page;
 
/*******************************************************************************
6. Issue the database query:
*******************************************************************************/
 
// This has been done already as below:
$query="SELECT * FROM `$tbl_tasks`, `$tbl_projects` where fk_id_pro_ctk = id_pro order by id_ctk asc $limit";
$result=mysql_query($query);
 
/*******************************************************************************
7. Construct pagination hyperlinks:
Finally, we must construct the hyperlinks which will allow the user to SELECT
other pages. We start with the links for any previous pages.
*******************************************************************************/
 
// a) If on page 1, it wont provide hyperlinks (yet), it will just echo FIRST PREV
 
if ($pageno == 1) {
      echo " FIRST PREV ";
} else {
      printf("<a href='%s'>FIRST</a>", "{$_SERVER['PHP_SELF']}?pageno=1");
      $prevpage = $pageno-1;
      printf("<a href='%s'>PREV</a>", "{$_SERVER['PHP_SELF']}?pageno={$prevpage}");
}
 
// b) We now inform the user of his current position in the sequence of available pages:
echo " ( Page $pageno of $lastpage ) ";
 
// c) This code will provide the links for any following pages:
 
if ($pageno == $lastpage) {
	echo " NEXT LAST ";
} else {
	$nextpage = $pageno+1;
	printf("<a href='%s'>NEXT</a>", "{$_SERVER['PHP_SELF']}?pageno=$nextpage");
	printf("<a href='%s'>LAST</a>", "{$_SERVER['PHP_SELF']}?pageno=$lastpage");
}
 
?>
 
 
 
 
==================================== display_records_only.php
<head>
<link rel="stylesheet" media="all" type="text/css" href="css/tasks.css" />
<link rel="stylesheet" media="all" type="text/css" href="css/main_page_styles.css" />
<script src="js/sorttable.js" type="text/javascript"></script>
<script src="js/showhide_div.js" type="text/javascript"></script>
<?php
include ("connectiondb.php");
$tbl_tasks="currenttasks_ctk";
$tbl_projects="projects_pro";
 
?>
</head>
 
<body>
<center><h3>Tasks Database</h3></center>
 
<!-- START OF DISPLAY RECORDS: on its own, the following displays all records no problem ############# -->
<?php
$query="SELECT * FROM `$tbl_tasks`, `$tbl_projects` where fk_id_pro_ctk = id_pro order by id_ctk asc $limit";
$result=mysql_query($query);
$numrows=mysql_num_rows($result);
?>
<table id="table_sort_all" class="sortable">
<thead><tr><td><b>ID</b></td><td><b>Task Name</b></td><td><b>Project</b></td><td><b>Description</b></td></tr></thead>	
<tbody>										
				
<?php
for ($i=0; $i < $numrows; $i++) {
$rows=mysql_fetch_array($result); // get a row from our result set
if($i % 2) { // if there is a remainder 
?>
<tr class="altRow_0">
 <?php
}
else { // if there is not a remainder we will do the else ?>
<tr class="altRow_1">
 <?php
} ?>						
<td id="viewtasksidall"><?php echo $rows['id_ctk']; ?></td>
<td id="viewtasksnameall"><?php echo stripslashes($rows['name_ctk']); ?></td>
<td id="viewtasksprojectall"><?php echo stripslashes($rows['name_pro']); ?></td>
<td id="viewtasksdescriptionall"><?php echo $rows['description_ctk']; ?></td>			
</tr> <?php } ?>					
</tbody>		
<tfoot></tfoot>		
</table> 
<!-- END OF DISPLAY RECORDS: ############# -->	
 
</body>
 
 
==================================== both_pagination_and_records.php
 
<head>
<link rel="stylesheet" media="all" type="text/css" href="css/tasks.css" />
<link rel="stylesheet" media="all" type="text/css" href="css/main_page_styles.css" />
<script src="js/sorttable.js" type="text/javascript"></script>
<script src="js/showhide_div.js" type="text/javascript"></script>
<?php
include ("connectiondb.php");
$tbl_tasks=	"currenttasks_ctk";
$tbl_projects="projects_pro";
?>
</head>
 
<body>
<center><h3>Tasks Database</h3></center>
 
 
<?php
 
/* xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx
Pagination Section:
xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx */
 
/*******************************************************************************
1: Get the required page number:
*******************************************************************************/
 
if (isset($_GET['pageno'])) {
	$pageno = $_GET['pageno'];	
} else {
	$pageno = 1;
}
echo "The current page number is: " . $pageno . "<br>";
 
/*******************************************************************************
2: Identify how many database rows are available:
This code will count how many rows will satisfy the current query.
*******************************************************************************/
$query="SELECT count(*) FROM `$tbl_tasks`, `$tbl_projects` where fk_id_pro_ctk = id_pro order by id_ctk asc";
$result = mysql_query($query);
$query_data = mysql_fetch_row($result);
$numrows = $query_data[0];
echo "The number of rows is: " . $numrows;
 
/*******************************************************************************
3: Calculate the number of the $lastpage:
This code uses the values in $rows_per_page (that you specify you want to show)
and $numofrows in order to identify the number of the last page.
*******************************************************************************/
 
$rows_per_page = 15;
$lastpage = ceil($numrows/$rows_per_page);
 
echo "The value of the last page in this case will be: " . $lastpage . "<br>";
 
 
/*******************************************************************************
4: Ensure that $pageno is within range:
This code checks that the value of $pageno is an integer between 1 and $lastpage
*******************************************************************************/
 
$pageno = (int)$pageno;
if ($pageno > $lastpage) {
	$pageno = $lastpage;
}
if ($pageno < 1) {
	$pageno = 1;
}
 
/*******************************************************************************
5: Construct LIMIT clause eg. How many rows to view for each page. eg. 10
This code will construct the LIMIT clause for the sql SELECT statement.
*******************************************************************************/
 
$limit = 'LIMIT' . ($pageno - 1) * $rows_per_page . ',' . $rows_per_page;
 
/*******************************************************************************
6. Issue the database query:
*******************************************************************************/
 
// This has been done already as below:
$query="SELECT * FROM `$tbl_tasks`, `$tbl_projects` where fk_id_pro_ctk = id_pro order by id_ctk asc $limit";
$result=mysql_query($query);
 
/*******************************************************************************
7. Construct pagination hyperlinks:
Finally, we must construct the hyperlinks which will allow the user to SELECT
other pages. We start with the links for any previous pages.
*******************************************************************************/
 
// a) If on page 1, it wont provide hyperlinks (yet), it will just echo FIRST PREV
 
if ($pageno == 1) {
      echo " FIRST PREV ";
} else {
      printf("<a href='%s'>FIRST</a>", "{$_SERVER['PHP_SELF']}?pageno=1");
      $prevpage = $pageno-1;
      printf("<a href='%s'>PREV</a>", "{$_SERVER['PHP_SELF']}?pageno={$prevpage}");
}
 
// b) We now inform the user of his current position in the sequence of available pages:
echo " ( Page $pageno of $lastpage ) ";
 
// c) This code will provide the links for any following pages:
 
if ($pageno == $lastpage) {
	echo " NEXT LAST ";
} else {
	$nextpage = $pageno+1;
	printf("<a href='%s'>NEXT</a>", "{$_SERVER['PHP_SELF']}?pageno=$nextpage");
	printf("<a href='%s'>LAST</a>", "{$_SERVER['PHP_SELF']}?pageno=$lastpage");
}
 
?>
 
 
<!-- START OF DISPLAY RECORDS: on its own, the following displays all records no problem ############# -->
<?php
$query="SELECT * FROM `$tbl_tasks`, `$tbl_projects` where fk_id_pro_ctk = id_pro order by id_ctk asc $limit";
$result=mysql_query($query);
// $numrows=mysql_num_rows($result);
?>
<br>
<table id="table_sort_all" class="sortable">
<thead><tr><td><b>ID</b></td><td><b>Task Name</b></td><td><b>Project</b></td><td><b>Description</b></td></tr></thead>	
<tbody>					
<?php
for ($i=0; $i < $numrows; $i++) {
$rows=mysql_fetch_array($result); 
if($i % 2) { // if there is a remainder 
?>
<tr class="altRow_0">
<?php
}
else { // if there is not a remainder we will do the else ?>
<tr class="altRow_1">
<?php
}?>							
<td id="viewtasksidall"><?php echo $rows['id_ctk']; ?></td>
<td id="viewtasksnameall"><?php echo stripslashes($rows['name_ctk']); ?></td>
<td id="viewtasksprojectall"><?php echo stripslashes($rows['name_pro']); ?></td>
<td id="viewtasksdescriptionall"><?php echo $rows['description_ctk']; ?></td>			
</tr> <?php } ?>					
</tbody>		
<tfoot></tfoot>		
</table> 
<!-- END OF DISPLAY RECORDS: ############# -->	
 
</body>
[+][-]10.04.2008 at 05:46PM PDT, ID: 22642826

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[+][-]10.04.2008 at 05:49PM PDT, ID: 22642832

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[+][-]10.04.2008 at 08:43PM PDT, ID: 22643326

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Zone: PHP Scripting Language
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Solution Provided By: hielo
Participating Experts: 2
Solution Grade: A
 
 
[+][-]10.04.2008 at 09:25PM PDT, ID: 22643419

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[+][-]10.04.2008 at 09:27PM PDT, ID: 22643421

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