subtract current time to end of day - php

This will do it as spec'd

<?php

$now = date("Y-m-d");
$tomorrow = strtotime("$now +1 day");
$timeLeft = $tomorrow - time();

echo date("H \h\o\u\\r\s i \m\i\\n\u\\t\e\s s \s\e\c\o\\n\d\s",$timeLeft);
?>

The escaping is to stop the date function interpreting the text as directives.

If you want to split out the hours etc then alter the above like so

<?php

$now = date("Y-m-d");
$tomorrow = strtotime("$now +1 day");
$timeLeft = $tomorrow - time();

$hours = date("H",$timeLeft);
$mins  = date("i",$timeLeft);
$secs  = date("s",$timeLeft);

echo "Time left is $hours hours, $mins minutes and $secs seconds";
?>

the 1st option gives me 4 hours instead of 9.

Well, it would do - there is only 4 hours (or so) to midnight - in this timezone.....

perfect, thanks!

OK here it is modified to use your example time (which gives 9 hours to go)

<?php
$sampleTime = strtotime("14:33:27");

$now = date("Y-m-d");
$tomorrow = strtotime("$now +1 day");
$timeLeft = $tomorrow - $sampleTime;

$hours = date("H",$timeLeft);
$mins  = date("i",$timeLeft);
$secs  = date("s",$timeLeft);

echo "Time left is $hours hours, $mins minutes and $secs seconds";
?>