Question

php drop down list onChange not submitting the form

Asked by: cyberwebservice

Hi,
This is a very simple code where I am populating a drop down list from mysql table PERIODS and upon selecting the value from the drop down, I want the starttime and endtime fields filled from the table PERIODS. Then the details are entered into another table on clicking the submit button.

I thought this is very simple and can be finished in 20 to 30 minutes. But I am struggling with this for more than 2 hours because the drop down change event does not do anything. I tried many variations and nothing works.

I don't want to use AJAX here, because, this code is to demonstrate to a beginner coder. Also, if you find anything insecure in the code, please feel free to tell me.

Thanks.

<? 
$host = "localhost";	//This is your mysql server host name
$db_user="lessons";//"dbuser";		//Substitute your Database user name here
$db_pwd="lessons";//"password";		//Substitute your Database user password here
$db_name="lessons";//"dbname";		// Your database name
$connection = mysql_connect($host, $db_user, $db_pwd)
or die (mysql_error()); //	'database_name' 
$db = mysql_select_db($db_name, $connection) or die (mysql_error());
?>
 
<?
$desc = mysql_real_escape_string($_POST['perioddesc']);
$query = "select * from periods order by Perioddesc";	//Querying the Periods table
$result = mysql_query($query) or die(mysql_error());	//Execute the Query
if($desc==""){
$option="<option>-- Select --</option>";
}else{
$option="<option>".$desc."</option>";
}
while($rs=mysql_fetch_array($result)){		// Fetch each record from the result set
$option.= "<option>".$rs['Perioddesc']."</option>";
}
?>
<?
if(isset($_POST['submit'])){
$desc = mysql_real_escape_string($_POST['perioddesc']);
$starttime = mysql_real_escape_string($_POST['starttime']);
$endtime = mysql_real_escape_string($_POST['endtime']);
$query = "insert into daylessons(lessondesc, starttime, endtime) values('$desc', '$starttime', '$endtime')";
$res = mysql_query($query) or die(mysql_error());
echo "Record inserted!";
}
?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" />
<title>Day Lessons</title>
<script language="javascript">
function callsubmit(){
var dform = document.getElementById("daylessonfrm");
dform.setAttribute("action", "insertlesson.php?action=displaytime");
document.getElementById("daylessonfrm").submit();
//document.getElementById("daylessonfrm").action="insertlesson.php?action=displaytime";
//document.getElementById("daylessonfrm").submit();
}
</script>
</head>
<body>
<?
if($_REQUEST['action']=="displaytime"){
$desc = mysql_real_escape_string($_POST['perioddesc']);
$db_query = "select * from periods where perioddesc='".$desc."'";
$resultset = mysql_query($db_query);
$rowset = mysql_fetch_array($resultset);
$starttime = $rowset['starttime'];
$endtime = $rowset['endtime'];
}
 
?>
<form name="daylessonfrm" id="daylessonfrm" action="insertlesson.php" method="post" >
<span>Period : <select name="perioddesc" id="perioddesc" onChange="callsubmit();">
<? echo $option; ?>
</select></span>
<br /><br />Start Time: <input type="text" name="starttime" id="starttime" value="<?=$starttime?>"  />
<br /><br />End Time: <input type="text" name="endtime" id="endtime" value="<?=$endtime?>"  />
<input type="submit" name="submit" value="submit"  />
</form>
</body>
</html>

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Asked On: 2009-05-26 at 05:35:48ID24437776
Topics: PHP Scripting Language
,; Web Languages/Standards
Participating Experts: 3
Points: 500
Comments: 5

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Answers

by: strickddPosted on 2009-05-26 at 06:03:08ID: 24472708

I would recommend putting an alert('test') in the callSubmit function and make sure it is actually executing. You may also need to tab out of the drop down for it to fire the event.

by: cmaohioPosted on 2009-05-26 at 06:04:11ID: 24472718

Is it submitting at all? Or is the javaScript submitting the initial time?

In Firefox, I know you, can bring up the error console and then try to execute the form and see what errors you get.

Perhaps instead of changing the action to include a querystring, perhaps have an empty hidden field: <input type="hidden" name="action" value=""/>

then use the JS to update that and submit.

by: cyberwebservicePosted on 2009-05-26 at 06:09:23ID: 24472782

Hi,

Sorry It works now. I was rephrasing the question, while you posted, it doen't allow me to edit it now :)

I am attaching the working code.

I am going to teach a beginner how it works. So, please leave my initial question and look at the other part of the code and suggest me if I can improve it keeping in mind the security and performance issues.

Thanks

<? 
$host = "localhost";	//This is your mysql server host name
$db_user="lessons";//"dbuser";		//Substitute your Database user name here
$db_pwd="lessons";//"password";		//Substitute your Database user password here
$db_name="lessons";//"dbname";		// Your database name
$connection = mysql_connect($host, $db_user, $db_pwd)
or die (mysql_error()); //	'database_name' 
$db = mysql_select_db($db_name, $connection) or die (mysql_error());
?>
 
<?
$desc = mysql_real_escape_string($_POST['perioddesc']);
$query = "select * from periods order by Perioddesc";	//Querying the Periods table
$result = mysql_query($query) or die(mysql_error());	//Execute the Query
if($desc==""){
$option="<option>-- Select --</option>";
}else{
$option="<option>".$desc."</option>";
}
while($rs=mysql_fetch_array($result)){		// Fetch each record from the result set
$option.= "<option>".$rs['Perioddesc']."</option>";
}
?>
<?
if(isset($_POST['Submit'])){
$desc = mysql_real_escape_string($_POST['perioddesc']);
$starttime = mysql_real_escape_string($_POST['starttime']);
$endtime = mysql_real_escape_string($_POST['endtime']);
$query = "insert into daylessons(lessondesc, starttime, endtime) values('$desc', '$starttime', '$endtime')";
$res = mysql_query($query) or die(mysql_error());
echo "Record inserted!";
}
?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" />
<title>Day Lessons</title>
<script language="javascript">
function callsubmit(){
var a=document.getElementById("daylessonfrm").action;
 
document.getElementById("daylessonfrm").action="insertlesson.php?action=displaytime";
var b=document.getElementById("daylessonfrm").action;
//alert(b);
document.getElementById("daylessonfrm").submit();
}
</script>
</head>
<body>
<?
if($_REQUEST['action']=="displaytime"){
$desc = mysql_real_escape_string($_POST['perioddesc']);
$db_query = "select * from periods where perioddesc='".$desc."'";
$resultset = mysql_query($db_query);
$rowset = mysql_fetch_array($resultset);
$starttime = $rowset['starttime'];
$endtime = $rowset['endtime'];
}
 
?>
<form name="daylessonfrm" id="daylessonfrm" action="insertlesson.php" method="post" >
<span>Period : <select name="perioddesc" id="perioddesc" onchange="this.form.action='insertlesson.php?action=displaytime';this.form.submit();">
<? echo $option; ?>
</select></span>
<br /><br />Start Time: <input type="text" name="starttime" id="starttime" value="<?=$starttime?>"  />
<br /><br />End Time: <input type="text" name="endtime" id="endtime" value="<?=$endtime?>"  />
<input type="submit" name="Submit" value="Submit" onclick="this.form.action='insertlesson.php'"  />
</form>
</body>
</html>

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by: vimalmariaPosted on 2009-05-26 at 08:23:23ID: 24474199

Hi,
function callsubmit(){
var a=document.getElementById("daylessonfrm").action;
document.getElementById("daylessonfrm").action="insertlesson.php?action=displaytime";
var b=document.getElementById("daylessonfrm").action;
document.getElementById("daylessonfrm").submit();
}

if not using "getElementById" u can use the following one

document.formname.submit();
this will work both in iexplore and firefox

some times the "getElementById" won't work

by: cyberwebservicePosted on 2009-05-26 at 09:57:54ID: 24475115

Hi,
That javascript is not called anywhere. I forgot to remove that from code.

20120131-EE-VQP-002

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Question

php drop down list onChange not submitting the form

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PHP Scripting Language

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