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8.4

show all record not only 1 record

Asked by teera in PHP Scripting Language, PHP and Databases, MySQL Server

how can i change the code to show many record not show only 1 record 
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<?php require_once('../Connections/aoldatabase.php'); 
if (isset($_POST['submitsearch']))
{
$names = $_POST['names'];
$address =$_POST['address'];
$tel =$_POST['tel']	;
echo " $names, a $address, t $tel ";
 
mysql_select_db($database_aoldatabase, $aoldatabase);
 
$query_Recordset1 = "SELECT customer.id, customer.name, customer.address, customer.tel, customer.mobile, customer.tel2 FROM customer where name like '%".$names."%' and address like '%".$address."%' and  (tel like '%".$tel."%' or tel2  like '%".$tel."%' or mobile like '%".$tel."%') ";
 
 
$Recordset1 = mysql_query($query_Recordset1, $aoldatabase) or die(mysql_error());
$row_Recordset1 = mysql_fetch_assoc($Recordset1);
$totalRows_Recordset1 = mysql_num_rows($Recordset1);
 
 
 
?>
 
 
<table width="925" border="1">
  <tr>
    <td width="116">&nbsp;</td>
    <td width="140">&nbsp;</td>
    <td width="157">&nbsp;</td>
    <td width="359">&nbsp;</td>
    <td width="8">&nbsp;</td>
    <td width="7">&nbsp;</td>
    <td width="20">&nbsp;</td>
    <td width="73">&nbsp;</td>
  </tr>
  <?php do { ?>
    <tr>
      <td><?php echo $row_Recordset1['id']; ?></td>
      <td><?php echo $row_Recordset1['name']; ?></td>
      <td><?php echo $row_Recordset1['address']; ?></td>
      <td><?php echo $row_Recordset1['tel']; ?>,<?php echo $row_Recordset1['tel2']; ?>,<?php echo $row_Recordset1['mobile']; ?></td>
      <td>&nbsp;</td>
      <td>&nbsp;</td>
      <td>&nbsp;</td>
      <td>&nbsp;</td>
    </tr>
    <?php } while ($row_Recordset1 = mysql_fetch_assoc($Recordset1)); ?>
<tr>
    <td>&nbsp;</td>
    <td>&nbsp;</td>
    <td>&nbsp;</td>
    <td>&nbsp;</td>
    <td>&nbsp;</td>
    <td>&nbsp;</td>
    <td>&nbsp;</td>
    <td>&nbsp;</td>
  </tr>
</table>
<p>&nbsp;</p>
</body>
</html>
<?php
mysql_free_result($Recordset1);
 
}
 
?>
 
 <form id="form1" name="searchfrom" method="post" action="<?php echo $_SERVER['PHP_SELF']?>">
  <label>search name
    <input type="text" name="names" id="name" />
  </label>
  <label>S Address
    <input name="address" type="text" id="address" size="35" />
  </label>
  <label>S tel
    <input name="tel" type="text" id="tel" size="15" />
  </label>
   <label>
    <input type="submit" name="submitsearch" id="submitsearch" value="SubmitSearch" />
  </label>
 
 
 
 
 
 
  
 
</form>
[+][-]10/22/09 10:50 PM, ID: 25641575Accepted Solution

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About this solution

Zones: PHP Scripting Language, PHP and Databases, MySQL Server
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Solution Provided By: Frosty555
Participating Experts: 2
Solution Grade: A
 
[+][-]10/22/09 10:59 PM, ID: 25641597Assisted Solution

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[+][-]10/22/09 11:01 PM, ID: 25641600Expert Comment

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[+][-]10/22/09 11:03 PM, ID: 25641614Author Comment

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