Thanks Michael701
If I echo $string I get:
0.jpg,1.jpg,2.jpg,3.jpg,4.
Which is the file name in the directory being opened.
Many thanks
Resna
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Browse All TopicsHi Guys.
I'm having problems with the below code. When I try and echo the end of the array 'echo end($i);' I don't have anything echo'ed.
I've tried test using:
$i = array(2,6,4,3,56,3);
echo end($i);
This works I get '3' echo'ed.
Can anyone see what I'm doing wrong?
Many thanks
Resna
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by: Michael701Posted on 2009-10-24 at 13:10:59ID: 25654059
are you sure $string is being built correctly?
try
echo $string; // before the expode.
maybe
if (eregi("\.jpg", $file)) {
should be
if (eregi("/.jpg", $file)) {