Question

display XML in HTML

Asked by: mcrmg

Hi,

Is there a way to display the following link in a html format?  thx

http://www.zillow.com/webservice/GetSearchResults.htm?zws-id=X1-ZWz1c5s42gbu2z_14qhc&address=2114+Bigelow+Ave&citystatezip=Seattle%2C+WA

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Asked On
2009-08-21 at 06:04:26ID24671206
Topics

Extensible HTML (XHTML)

,

Extensible Stylesheet Language Transformation (XSLT)

,

Cascading Style Sheets (CSS)

,

Web Languages/Standards

Participating Experts
4
Points
500
Comments
35

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Answers

 

by: KravimirPosted on 2009-08-21 at 21:15:11ID: 25157371

That's the kind of thing that XSL is used for. I'll request that a moderator add this question to the XSL zone for you.

 

by: GertonePosted on 2009-08-22 at 04:13:32ID: 25158252

What do you have and what do you want?

I have a link to an XML document, and basically that is it
- do you need in-page javascript that gets this page?
- do you simply want this transformed into XHTML?
- do you need some .net or java code that fetches the XML and renders XHTML?

Part of the question indeed will require XSLT, but is that all you need?

 

by: GertonePosted on 2009-08-22 at 04:20:12ID: 25158272

this would be a start for an XSLT, but now you need to say what exactly you want, how in the html

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
    <xsl:template match="/">
        <html>
            <head/>
            <body>
                <xsl:apply-templates select="//response/results/result"/>
            </body>    
         </html>
    </xsl:template>
    
    <xsl:template match="result">
        <table>
            <tr>
                <th>zpid</th>
                <td><xsl:value-of select="zpid"/></td>
            </tr>
            <xsl:for-each select="links/*">
                <tr>
                    <th><xsl:value-of select="name()"/></th>
                    <td><xsl:value-of select="."/></td>
                </tr>
            </xsl:for-each>
        </table>
    </xsl:template>
 
</xsl:stylesheet>
                                              
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by: pravinasarPosted on 2009-08-22 at 04:39:19ID: 25158315

I have a generic Javascript function, which creates a HTML table from any XML file.

Check this out at

http://javascriptjournal.com/ws/?p=14

http://javascriptjournal.com/tutorials/createXmlTable.htm

 

by: GertonePosted on 2009-08-22 at 06:34:21ID: 25158635

> I have a generic Javascript function, which creates a HTML table from ANY XML file.

If I read this, I am obviously very curious.
As self-advertisment this is very nice, but the statement is soo untrue.
I was particularly interested in what you have to offer on deeply nested XML structures
... and I found nothing at all. This code handles tabular XML data, that is it, and that is not even 10% of all XML data around.
I think the "ANY" should read "AN", because it literally looks for the "BOOK" element

> var x = xmlDoc.getElementsByTagName('BOOK')

Even then I should note that the code is not up to standard modern technology,
you are using a microsoft parser, still present in the microsoft msxml.dll,
but one you should have stopped using at least 8, if not 10 years ago

>xmlDoc = new ActiveXObject("Microsoft.XMLDOM");

It is common to use msxml2 these days, not only because it is more standardised and less buggy , but more memory friendly and fast

So, be carefull if you advertise your own solutions above their value.
People that come here with questions are looking for high quality solutions, not commercials

 

by: julianmatzPosted on 2009-08-22 at 10:15:55ID: 25159430

Here's another option. You could take the XML data and output the data using PHP's SimlpeXML.

http://php.net/simplexml

 

by: mcrmgPosted on 2009-08-22 at 11:10:54ID: 25159633

As you can see in the querystring in the url I posrted, it has address, I want to know how I can display it in HTML, so it is more readable....

We are using class ASP, I want to have a form that user can enter address and return back in XHTML  thanks


thanks

 

by: GertonePosted on 2009-08-23 at 16:46:15ID: 25164787

Something like this should do the trick,
given you save my XSLT as "listing.xsl"

<% @Language = "VBScript" %>
<%
Dim oXML
Set oXML = Server.CreateObject("MSXML2.DOMDocument")
Dim oXSL
Set oXSL= Server.CreateObject("Msxml2.FreeThreadedDOMDocument")
Dim oTmpl
Set oTmpl= Server.CreateObject("Msxml2.XSLTemplate")
Dim oProc
 
oXSL.async = false
oXSL.load Server.MapPath("listing.xsl")
 
oXML.validateOnParse = true
oXML.setProperty "ServerHTTPRequest", True
oXML.Load "http://www.zillow.com/webservice/GetSearchResults.htm?zws-id=X1-ZWz1c5s42gbu2z_14qhc&address=2114+Bigelow+Ave&citystatezip=Seattle%2C+WA"
 
oTmpl.stylesheet = oXSL
 
Set oProc= oTmpl.createProcessor()
oProc.input = oXML
 
oProc.output = Response
oProc.transform()
 
%>
                                              
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by: mcrmgPosted on 2009-08-24 at 06:20:00ID: 25167979

I tried the code above, I got a black page.  ZPID is not showing, I was wondering if you could help me with this..thaks

 

by: GertonePosted on 2009-08-24 at 06:25:02ID: 25168020

I can't debug this from a distance, or very difficult.
How much ASP experience do you have?
Can you check the objects for content
(meaning: is the XML loaded correctly, is the XSL loaded correctly, ...)

 

by: mcrmgPosted on 2009-08-24 at 06:39:16ID: 25168164

I am okay with ASP, I think the problem is with the xsl tags. (I think)
in your xsl file, it says the following, the parent tag for ZPID is RESULT, above RESULT, there are two more tags, RESULTS and RESPONSE.  I dont have much expeiense with XML..thx

 

by: GertonePosted on 2009-08-24 at 08:51:54ID: 25169547

I have an apply-templates that goes directly there, but lets make a test
change your XSLT to this one, and tell me what you see

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
<xsl:template match="/">
    <html>
        <body>
            <h1>You can see me, don't you?</h1>
        </body>
    </html>
</xsl:template>
</xsl:stylesheet>
                                              
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by: mcrmgPosted on 2009-08-24 at 09:21:53ID: 25169872

I got "You can see me, don't you?" big..thx

 

by: GertonePosted on 2009-08-24 at 12:19:05ID: 25171464

OK, the code doesn't crash out, that is good and the XSLT is working.
Let us now see whether the XML is loaded correctly
Try this XSLT

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
    <xsl:template match="/">
        <html>
            <body>
                <h1>Here comes the root element</h1>
                <p>
                    <xsl:value-of select="name(*)"/>
                 </p>
            </body>
        </html>
    </xsl:template>
</xsl:stylesheet>
                                              
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by: mcrmgPosted on 2009-08-24 at 12:50:32ID: 25171784

okay, I have "Here comes the root element" big..thx

 

by: GertonePosted on 2009-08-24 at 13:24:24ID: 25172201

OK, but no name for the root element underneath that?
That means that the XML is not loaded correctly.
Can you check that?
You might need to check some references on loading XML using VBScript in ASP
(I am not a real serious ASP programmer)

I go to bed now and am not available tomorrow, I will pick up from here on wednesday

 

by: mcrmgPosted on 2009-08-25 at 05:04:52ID: 25176569

This is what I used, I dont know if I am testing the right thing.  Please help..thx

Response.Buffer = True
Dim xml
Set xml = Server.CreateObject("Microsoft.XMLDOM")
xml.async = False
xml.load("http://www.zillow.com/webservice/GetSearchResults.htm?zws-id=X1-ZWz1c5s42gbu2z_14qhc&address=2114+Bigelow+Ave&citystatezip=Seattle%2C+WA")
   If xml.parseError.errorCode <> 0 Then
      response.write "XML Error"
      response.Write ("Parse Error line " & xml.parseError.line & ", character " & _
       xml.parseError.linePos & vbCrLf & xml.parseError.srcText)
 

   else
      response.write "Good XML"
   End If

 

by: GertonePosted on 2009-08-25 at 05:09:10ID: 25176606

seems like a good test,
but you need to use a more modern XML object
Server.CreateObject("MSXML2.DOMDocument")

 

by: mcrmgPosted on 2009-08-25 at 05:27:48ID: 25176735

I received "XML ErrorParse Error line 0, character 0 "


does it mean XML is good?  thx

 

by: GertonePosted on 2009-08-25 at 05:31:05ID: 25176772

No, "Error" usually means it is not good.

There seems to be an issue loading the XML,
maybe there is an issue with the schema

 

by: mcrmgPosted on 2009-08-25 at 05:36:26ID: 25176821

I used another url to test, and still have error

http://www.zillow.com/webservice/GetZestimate.htm?zws-id=X1-ZWz1c5s42gbu2z_14qhc&zpid=48749425

If there is an issue with schema, where can I start?  thx
http://www.zillow.com/howto/api/GetZestimate.htm

 

by: GertonePosted on 2009-08-25 at 05:46:00ID: 25176905

well, they are all from the same site,
there might be a issue because of restrictions on the site.
Can you try with an XML from a completely different URL?

 

by: mcrmgPosted on 2009-08-25 at 05:53:17ID: 25176976

okay, I could not find one, so I the xml file form here
http://msdn.microsoft.com/en-us/library/ms762271(VS.85).aspx
and save it as x.xml and call it from the asp page like this, I am still getting this only, no name..thx
"Here comes the root element"

<% @Language = "VBScript" %>
<%
Dim oXML
Set oXML = Server.CreateObject("MSXML2.DOMDocument")
Dim oXSL
Set oXSL= Server.CreateObject("Msxml2.FreeThreadedDOMDocument")
Dim oTmpl
Set oTmpl= Server.CreateObject("Msxml2.XSLTemplate")
Dim oProc
 
oXSL.async = False
oXSL.load Server.MapPath("listing.xsl")
 
oXML.validateOnParse = True
oXML.setProperty "ServerHTTPRequest", True
oXML.Load "x.xml"
 
oTmpl.stylesheet = oXSL
 
Set oProc= oTmpl.createProcessor()
oProc.input = oXML
 
oProc.output = Response
oProc.transform()
 
%>

 

by: GertonePosted on 2009-08-25 at 06:05:52ID: 25177084

If you save the XML as a file, you need to load it differently
 
oXML.async = False
oXML.validateOnParse = True
oXML.load Server.MapPath("x.xml")

That is because you no longer load it from a httpserver

 

by: mcrmgPosted on 2009-08-25 at 06:20:29ID: 25177246

hmm...it works....

 

by: mcrmgPosted on 2009-08-25 at 06:28:22ID: 25177324

so you would think it is something wrong with the XSD?  thx

 

by: GertonePosted on 2009-08-25 at 06:31:05ID: 25177357

now try to download and save the zillow file,
then make a httprequest for fetching the file directly

 

by: mcrmgPosted on 2009-08-25 at 06:46:09ID: 25177518

okay, I copied and pasted it to a notepad, I deleted all the "-", and it works.....thx

 

by: GertonePosted on 2009-08-25 at 06:47:56ID: 25177542

welcome

 

by: mcrmgPosted on 2009-08-25 at 07:06:25ID: 25177717

so anyway that I can get it to work on line?  thx

 

by: GertonePosted on 2009-08-25 at 07:12:12ID: 25177771

well, our next step is to make sure that the XML is effectively loaded using this code

oXML.validateOnParse = true
oXML.setProperty "ServerHTTPRequest", True
oXML.Load "http://www.zillow.com/webservice/GetSearchResults.htm?zws-id=X1-ZWz1c5s42gbu2z_14qhc&address=2114+Bigelow+Ave&citystatezip=Seattle%2C+WA"

maybe there are restrictions.
I can't look into that right now, since I am at a customers location behind a firewall.
But why don't you ask a parallel question on the ASP track, to see if these three lines have restrictions in an ASP environment.
All what is left for us to do now is
- get the dynamic load working => ask the ASP forum for that
- change my XSLT to give you exactly what you need => come back here for that later

 

by: GertonePosted on 2009-08-25 at 07:14:45ID: 25177804

It would really be beneficial I think if you switched validation off
oXML.validateOnParse = false

 

by: mcrmgPosted on 2009-08-25 at 07:24:19ID: 25177911

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