Question

Select Nodes with Names Like ?

Asked by: sherly

By using xpath, i can retrieve first MarkTemplate's ObjectText with MarkObjectType='TEXT' using this syntax :
var MatchingNodes=theRoot.selectNodes("//MarkTemplate[0]/MarkingObjects/MarkObject[MarkObjectType='TEXT']/ObjectText");

What is the syntax if I want to select all nodes of first MarkTemplate with node name begin with "Image" which select "ImageId1","ImageId2","ImageId3" ?

This is my xml :

<?xml version="1.0" encoding="utf-8"?>
<ArrayOfMarkTemplate>
  <MarkTemplate>
    <MarkType>MARKTYPE001</MarkType>
    <ImageId1>854</ImageId1>
    <ImageId2>999</ImageId2>
    <ImageId3>394</ImageId3>
    <MarkingObjects>
      <MarkObject>
        <MarkObjectType>TEXT</MarkObjectType>
        <ObjectText>TEXT001</ObjectText>
        <MarkMethod></MarkMethod>
        <MarkInfo>Info</MarkInfo>
      </MarkObject>
      <MarkObject>
        <MarkObjectType>TEXT</MarkObjectType>
        <ObjectText>TEXT002</ObjectText>
        <MarkInfo>Info</MarkInfo>
       </MarkObject>
      <MarkObject>
        <MarkObjectType>TEXT</MarkObjectType>
        <ObjectText>TEXT003</ObjectText>
       <MarkInfo>Info001</MarkInfo>      
      </MarkObject>
      <MarkObject>
        <MarkObjectType>GRAPHIC</MarkObjectType>
        <ObjectText>GRAPHIC001</ObjectText>
       <MarkInfo>Info004</MarkInfo>
      </MarkObject>
    </MarkingObjects>
  </MarkTemplate>
  <MarkTemplate>
   ......
  </MarkTemplate>
</ArrayOfMarkTemplate>

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Asked On
2006-11-11 at 05:04:07ID22057117
Tags

like

,

xml

Topic

Extensible Markup Language (XML)

Participating Experts
1
Points
300
Comments
9

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Answers

 

by: GertonePosted on 2006-11-11 at 05:06:39ID: 17921065

Hi sherly,

you can use starts-with() on the name()

var MatchingNodes=theRoot.selectNodes("//MarkTemplate[0]/*[starts-with(name(), 'Image')]")

Cheers!

 

by: sherlyPosted on 2006-11-11 at 05:14:56ID: 17921093

I'm having an unknown method error, please advise.

 

by: sherlyPosted on 2006-11-11 at 05:18:15ID: 17921106

Error : Unknown method
//MarkTemplate[0]/*[-->starts-with(name<--(),'Image')]

 

by: GertonePosted on 2006-11-11 at 05:28:20ID: 17921148

sherly,

you have to use a more modern version of the msxml parser
you are likely using msxml3, but in version1 mode, not in version2 mode
you should definitely use the parser in version 2 mode
but it is even better to upgrade to msxml4 (download from microsoft web, it leaves the msxml3 in place, so nothing breaks)
microsoft was too late supporting some of the XPath functions in their parser

Can you show me the line where you create theRoot
(the thing with MSXML.DOM or whatever)
I will then send you an alternative

In the mean time you can test this
var MatchingNodes=theRoot.selectNodes("//MarkTemplate[0]/*[substring(name(), 1, 6) = 'Image']")

cheers

Geert

 

by: sherlyPosted on 2006-11-11 at 05:35:22ID: 17921165

Hi, I'm very new in XML. These are the only 2 lines which I declared theRoot. My xml data is on the html itself, the <xml id="xmldata"></xml> of the portion. I'm using IE6 and I don't know which version of MSXML I'm using. Please guide me in the proper way to declare the DOM. I'm increasing question point to 300. Thanks for your help.

// initialize objects
this.xmldoc = document.getElementById("xmldata");
                                                            
//Get the root
var theRoot = this.xmldoc.documentElement;

 

by: sherlyPosted on 2006-11-11 at 05:36:36ID: 17921169

I tried :
var MatchingNodes=theRoot.selectNodes("//MarkTemplate[0]/*[substring(name(), 1, 6) = 'Image']")

but it is returning more elements than I expected.

 

by: sherlyPosted on 2006-11-11 at 05:47:54ID: 17921198

sorry, I was using var MatchingNodes=("//MarkTemplate[0]/*[substring(name(), 1, 6) = 'Image']") just now. I missed out the Root.selectNodes.

Now, I tried var MatchingNodes=theRoot.selectNodes("//MarkTemplate[0]/*[substring(name(), 1, 6) = 'Image']") and I got unknown method error.

 

by: GertonePosted on 2006-11-11 at 05:55:43ID: 17921217

sherly,

mmh, I am not sure this kind of IE internal processing allows for the proper selection of the parser
IE6 comes with msxml3

I found two little bugs in the XPath
the 0 should be 1 ofcourse
and Image has only 5 characters instead of 6 :-)

This one works perfectly for me
var MatchingNodes=theRoot.selectNodes("//MarkTemplate[1]/*[substring(name(), 1, 5) = 'Image']")

 

by: GertonePosted on 2006-11-11 at 06:08:23ID: 17921248

sherly,

well, it seems you also don't have access to the substring() function

I see two options for you here

1. fully express all the names
var MatchingNodes=theRoot.selectNodes("//MarkTemplate[1]/*[name() = 'ImageId1' or name() = 'ImageId2' or name() = 'ImageId3']")

2. make the XML external to the HTML
and call it in, with the proper document object creator,
if that is acceptable for you

         var oXML = new ActiveXObject("Msxml2.DOMDocument.4.0");
         oXML.async = false;
         oXML.resolveExternals = false;
         oXML.load("yourFile.xml");  
         var MatchingNodes=oXML.selectNodes("//MarkTemplate[1]/*[substring(name(), 1, 5) = 'Image']")

If you don't install msxml4,
this could work as well
         var oXML = new ActiveXObject("Msxml2.DOMDocument.3.0");
you would then use msxml3 in version2 mode

cheers

Geert

 

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