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01.19.2007 at 12:05PM PST, ID: 22129357
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9.8

EASY: XSLT loop through first 5 elements only

Asked by peh803 in Extensible Markup Language (XML)

Tags: , , ,

I am sure this is simple -- but I'm new to XSLT -- so thanks in advance for helping me with what I'm sure is an easy question.

I am reading an RSS feed that has a lot of stuff in it -- and I want to show only the first "x" articles, not all of them.

How can I modify this code to do that?
      <xsl:for-each select="item">
         <li>
            <a>
               <xsl:attribute name="href">
                  <xsl:value-of select="link" />
               </xsl:attribute>
               <xsl:attribute name="target">_blank</xsl:attribute>
               <xsl:value-of select="title" disable-output-escaping="yes"  />
            </a>
            <br/>
               <xsl:value-of select="description" disable-output-escaping="yes"  />
         </li>
        </xsl:when>
      </xsl:for-each>

I've tried stuff like this:
        <xsl:when test="position() < 5">
        <.xsl:when>

But I'm just not quite getting it.

Thanks in advance for your help with this.

Regards,
PhilStart Free Trial
[+][-]01.19.2007 at 12:08PM PST, ID: 18352034

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About this solution

Zone: Extensible Markup Language (XML)
Tags: loop, xslt, through, xsl
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Solution Provided By: Gertone
Participating Experts: 1
Solution Grade: A
 
 
[+][-]01.19.2007 at 12:14PM PST, ID: 18352079

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[+][-]01.19.2007 at 12:21PM PST, ID: 18352150

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[+][-]01.19.2007 at 12:35PM PST, ID: 18352284

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[+][-]01.19.2007 at 12:39PM PST, ID: 18352322

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