Suposse this xml
<xml>
<ref value="24.3">
<values>
<any value="93.7" id="A"/>
<any value="15.7" id="B"/>
<any value="6.11" id="C"/>
<any value="48.76" id="D"/>
<any value="32.8" id="E"/>
<any value="24.1" id="F"/>
</values>
</xml>
How can I do
<xslt:for-each select "/xml/values/any/">, but sorted by the ABSOLUTE value of the difference between /xml/ref/@value and each "/xml/values/any/@value
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I perfectly realize that this is VERY obscure :-)
XSLT1 has no function for the absolute value of a number
so...
((../../ref/@value - @value) < 0)) is false or true, casted to a number, false would be 0 and true would be 1
so the multiplier will be 1 for positive numbers and -1 for negative numbers, hence creating an absolut value
sorry, not the most comprehensible answer ever, but the only way to do this here
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Answer for Membership
by: GertonePosted on 2009-10-29 at 11:30:17ID: 25696659
<xsl:for-each select="xml/values/any">
<xsl:sort select="(1 - 2 * ((../../ref/@value - @value) < 0)) * (../../ref/@value - @value)"/>
<xsl:copy-of select="."/>
</xsl:for-each>