Hi!
It has been a while since I worked with XSLT, and now I have severe brain damage from switching back and forth working with JavaScript and PHP.
Anyhow, I need some help with XSLT/Xpath, if anyone has some time.
I need to get the current node number.
Let's say there is 5 nodes with the name sugarDaddy, I need to know which number I am currently at (when applying a template).
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I've been testing some things and it seems that I have to give a little bit more info...
This is exactly what I am trying to do:
<xsl:call-template name="template">
<xsl:with-param name="node" select="/root/node1/node2/
<xsl:with-param name="count" select="/root//x"/>
</xsl:call-template>
<xsl:template name="template">
<xsl:for-each select="$node">
<xsl:number level="any" count="$count" />
</xsl:for-each>
</xsl:template>
The above doesn't seem to work. If I however remove the "$count" and set the count value to "/root//x" things seem to go forwards...
I need some fresh ideas on how to solve this, it seems...
Well, I took care of the problem from a different angle... I think...
I will however leave this question open ('cause I ain't got m'self an answer).
Anyway, anyone that could answer the question:
"Why you can't pass a variable through xsl:number/count()"
Got themselves a 500 points * A. Couldn't be simpler could it?
Hi numbers1to9,
sorry for leaving you on this, I went to bed not so long after my initial post (I am on CET, 1AM ain't that bad :-)
You can't simply pass nodes or variables to xsl:number,
cause xsl:number counts nodes at the context node
so your observation is right that you need to switch to the context in the template to get the count right
<xsl:template name="template">
<xsl:for-each select="$node">
...
Now (...) is in the context of $node and does get the count right
The other problem you are experiencing has nothing to do with xsl:number but is a more general issue
xsl:number/@count takes an XPath expression, not a string value
In XSLT, there is no such thing as dynamically evaluated XPaths
If you pass an XPath, like this
<xsl:with-param name="count" select="/root//x"/>
not the string "/root//x" is passed but the nodeset of all 'x' nodes found at any depth below the node 'root' that is a child of the current context will be passed
If you wanted to pass the XPath expression a a string (so avoid early evaluation), you need to do this (add single quotes)
<xsl:with-param name="count" select="'/root//x'"/>
but that will not help you, since the string will not be evaluated as a dynamic XPath in the template
There are ways around this,
you could compare the name of an element (which is a string) to the variable string in a predicate in an XPath
(that is as close as dynamic XPaths as you will ever get)
Here is an example (note that I pass the element name as a string with single quotes)
This technique will not work if you wanted root//x instead of x.
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.o
<xsl:template match="/">
<xsl:call-template name="template">
<xsl:with-param name="node" select="/root/node1/node2/
<xsl:with-param name="count" select="'x'"/>
</xsl:call-template>
</xsl:template>
<xsl:template name="template">
<xsl:param name="node"/>
<xsl:param name="count"/>
<xsl:for-each select="$node">
<xsl:number level="any" count="*[name() = $count]" />
</xsl:for-each>
</xsl:template>
</xsl:stylesheet>
cheers
Geert
While I must say that sleep is for the week, you sure are great!
Thanks for your explanation and your example. I used a different method from the one you gave; magic--that's right magic.
I was so tired last night so I just moved around stuff until it worked. Actually I just "for-each"-ed the node in question and used simple number@level=any to get the position, yeah I know, isn't it funny? -- one could have nothing less than a love/hate relation to the X-family.
But I have saved your example as a fall-back if [when] my method bits the dust. I was looking for a Xpath expression similar the one you gave (count="*[name() = $count]") I just couldn't remember enough of Xpath to do that (getElementById in PHP/JavaScript [DOM] sure makes you lazy ;))
Cheers, alcohol and bloody broken glass!
Business Accounts
Answer for Membership
by: GertonePosted on 2007-08-09 at 14:55:53ID: 19666347
use xsl:number
<xsl:template match="sugarDaddy">
<xsl:number count="sugarDaddy" level="any" />
</xsl:template>
cheers
Geert