note that I changed the matches in the templates, I did that for testing, so you need to chnage them back to original
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Browse All TopicsHi there,
I am trying to get the current date in my XSLT but unavailable to achieve it.
The following is an example of my XSLT using the EXSLT but it is not working. It is complaining that it doesnt recognise the template.
Any clues anyone? thanks
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.o
<xsl:import href="date.msxsl.xsl"/>
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:template match="/parent">
<parent>
<xsl:apply-templates/>
</parent>
</xsl:template>
<xsl:template match="children">
<ChildFound>
<xsl:call-template name="date:date-time()"/>
</ChildFound>
</xsl:template>
</xsl:stylesheet>
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by: GertonePosted on 2007-09-18 at 23:21:11ID: 19918590
There are two little bugs in your stylesheet
rg/1999/XS L/Transfor m" xmlns:date="http://exslt.o rg/dates-a nd-times" extension-element-prefixes ="date">
1. your date namespace is not the same as the one in the imported stylesheet (you have spaces instead of dashes)
2. the msxsl date functions, are functions, not named templates
This one works
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.o
<xsl:import href="date.msxsl.xsl"/>
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:template match="/nvp">
<parent>
<xsl:apply-templates/>
</parent>
</xsl:template>
<xsl:template match="new">
<ChildFound>
<xsl:value-of select="date:date()"/>
</ChildFound>
</xsl:template>
</xsl:stylesheet>
cheers
Geert