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07/04/2009 at 07:25PM PDT, ID: 24544420
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9.0

XML Sort on attribute using xsl:sort

Asked by Bagur in Extensible Stylesheet Language Transformation (XSLT), Extensible HTML (XHTML), XPath

Tags: XM attribute Sort, xsl:sort

Hi,
I need to sort an xml document by an attribute. I am unable to do this by using the attached xsl stylesheet. Please help.

I need to sort the below document (dataField Nodea) by it's Table_Id attribute

As I said the above xslt does not work for sorting on Table_Id attribute, although the same thing works for Node_Id attribute if I just replace "DataField/@Table_Id" with "DataField/@Node_Id" in xslt. I am completely baffled by it's behavior. I am using VB6 (I think that should not matter).

I am very concerned as to why it works with one field and not the other.

Any help with some explaination is greatly appreciated.

Thanks in advance 
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My xml document
-----------------------------
<SubCompetency Node_Id = "3" Node_Name = "SubComp1">
    <DataField
        Table_Id = "14"
        Node_Id = "13"
        Node_Name = "Data1"
        ReqToCmp = "1"
        Def_Val = "NULL">
        <HtmField Node_Id = "16" Node_Name = "Field1">
            <HtmGrpField
                Node_Id = "79"
                Node_Name = "Grp1"
                Node_Val = "5"/>
            <HtmGrpField
                Node_Id = "80"
                Node_Name = "Grp2"
                Node_Val = "4"/>
            <HtmGrpField
                Node_Id = "81"
                Node_Name = "Grp3"
                Node_Val = "3"/>
            <HtmGrpField
                Node_Id = "82"
                Node_Name = "Grp4"
                Node_Val = "2"/>
            <HtmGrpField
                Node_Id = "83"
                Node_Name = "Grp5"
                Node_Val = "1"/>
            <HtmGrpField
                Node_Id = "84"
                Node_Name = "Grp6"
                Node_Val = "0"/>
        </HtmField>
    </DataField>
    <DataField
        Table_Id = "8"
        Node_Id = "25"
        Node_Name = "Data2"
        ReqToCmp = "1"
        Def_Val = "NULL">
        <HtmField Node_Id = "28" Node_Name = "Field2">
            <HtmGrpField
                Node_Id = "151"
                Node_Name = "Grp1"
                Node_Val = "5"/>
            <HtmGrpField
                Node_Id = "152"
                Node_Name = "Grp1"
                Node_Val = "4"/>
            <HtmGrpField
                Node_Id = "153"
                Node_Name = "Grp1"
                Node_Val = "3"/>
            <HtmGrpField
                Node_Id = "154"
                Node_Name = "Grp4"
                Node_Val = "2"/>
            <HtmGrpField
                Node_Id = "155"
                Node_Name = "Grp5"
                Node_Val = "1"/>
            <HtmGrpField
                Node_Id = "156"
                Node_Name = "Grp6"
                Node_Val = "0"/>
        </HtmField>
    </DataField>
    <DataField
        Table_Id = "3"
        Node_Id = "26"
        Node_Name = "Data3"
        ReqToCmp = "1"
        Def_Val = "NULL">
        <HtmField Node_Id = "29" Node_Name = "Field3">
            <HtmGrpField
                Node_Id = "157"
                Node_Name = "Grp1"
                Node_Val = "5"/>
            <HtmGrpField
                Node_Id = "158"
                Node_Name = "Grp2"
                Node_Val = "4"/>
            <HtmGrpField
                Node_Id = "159"
                Node_Name = "Grp3"
                Node_Val = "3"/>
            <HtmGrpField
                Node_Id = "160"
                Node_Name = "Grp4"
                Node_Val = "2"/>
            <HtmGrpField
                Node_Id = "161"
                Node_Name = "Grp5"
                Node_Val = "1"/>
            <HtmGrpField
                Node_Id = "162"
                Node_Name = "Grp6"
                Node_Val = "0"/>
        </HtmField>
    </DataField>
</SubCompetency>
------------------------------------------------------
 
My Xsl stylesheet
---------------------------------------------------------
 
<?xml version="1.0" encoding="UTF-8"?>"
    <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">"
    <xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>"
    <xsl:template match="SubCompetency|@*">"
    <xsl:copy><xsl:apply-templates select="node()|@*">"
    <xsl:sort select="DataField/@Table_Id" data-type="number" order="descending"/>"
    </xsl:apply-templates></xsl:copy></xsl:template>"
    <xsl:template match="node()|@*"><xsl:copy><xsl:apply-templates select="node()|@*"/>"
    </xsl:copy></xsl:template></xsl:stylesheet>"
--------------------------------------------------------------
[+][-]07/05/09 04:35 AM, ID: 24779667

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[+][-]07/05/09 02:29 PM, ID: 24781371

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[+][-]07/05/09 02:36 PM, ID: 24781379

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About this solution

Zones: Extensible Stylesheet Language Transformation (XSLT), Extensible HTML (XHTML), XPath
Tags: XM attribute Sort, xsl:sort
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Solution Provided By: Gertone
Participating Experts: 1
Solution Grade: A
 
 
[+][-]07/05/09 02:37 PM, ID: 24781385

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[+][-]07/05/09 02:41 PM, ID: 24781398

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