Question

XSLT for each loop

Asked by: critto

Hi experts,

Just a quick question regarding xml to xslt..

If i have a nested repeating element in xml, how do i transform it using xslt? example below:

I'm not getting the information that I should be in the for-loop. the rest works fine.

xml document:
 
                    <root>
                      <email></email>
                      <firstName></firstName>
                      <lastName></lastName>
                      <messageContent></messageContent>
                      <bookingId></bookingId>
                      <headline></headline>
                      <externalAdvertId></externalAdvertId>
                      <externalUserId></externalUserId>
                      <messageRequestURL></messageRequestURL>
                      <publications>
                        <paper>
                            <where></where>
                            <when></when>
                        </paper>
                      </publications>
                    </root>       
 
 
xslt document:
 
 <table border="0">
          <tr>
            <td width="150px">
              <strong>- Publication: </strong>
            </td>
            <td width="150px">
              <strong>- Date:</strong>
            </td>
          </tr>
          <xsl:for-each select="//root/publications/paper" >
            <tr>
              <td width="150px">
                <xsl:value-of select="/where" />
              </td>
              <td width="150px">
                <xsl:value-of select="/when" />
              </td>
            </tr>
          </xsl:for-each>
        </table>
 
sample xml document with data:
 
    <root>
      <email> Test@Test.com</email>
      <firstName> Test </firstName>
      <lastName> Test </lastName>
      <messageContent>Your ad below has just expired:</messageContent>
      <bookingId>2104311</bookingId>
      <headline>test</headline>
      <externalAdvertId>B2DA2115-C046-4B03-9975-6FBFC18F3DBF</externalAdvertId>
      <externalUserId>847EBB0E-B6F7-4A5C-9B11-AB966FC899AC</externalUserId>
      <messageRequestURL>test.com</messageRequestURL>
      <publications>
        <paper>
          <where> Test </where>
          <when>01/07/2009</when>
        </paper>
        <paper>
          <where> Test </where>
          <when>03/07/2009</when>
        </paper>
        <paper>
          <where>Test</where>
          <when>05/07/2009</when>
        </paper>
      </publications>
    </root>

                                  
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Asked On
2009-07-23 at 07:29:16ID24594646
Tags

xslt

,

c#

,

xml

Topics

Extensible Stylesheet Language Transformation (XSLT)

,

.NET Framework 2.x

Participating Experts
2
Points
500
Comments
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Answers

 

by: stevehardonPosted on 2009-07-23 at 12:21:25ID: 24929052

You might have left it out for clarity, but to be clear your xml data document should start with:
<?xml version="1.0" encoding="UTF-8"?>

Your style sheet should start with:

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
    <xsl:template match="/">

and end with:

        </xsl:template>
</xsl:stylesheet>

Then simply remove the starting "/" character in you value-of select statement like this:
<xsl:value-of select="where" />
and
<xsl:value-of select="when" />

 

by: crittoPosted on 2009-07-24 at 01:43:39ID: 24933079

Thanks for your response steve.

I can confirm that I have all the right document tags.. i left them out for brevity. I have stripped the / character from my value-of selects, however I still don't get the information that I should get.

The rest of the document works perfectly. It's only the loop that isn't displaying the info.

Any more ideas??

 

by: TiggeritoPosted on 2009-07-24 at 02:02:15ID: 24933163

Is it looping and not getting the data or not even looping?

Could you provide the example output

 

by: crittoPosted on 2009-07-24 at 03:28:55ID: 24933526

actually, it works. i had to restart my emailer service. ;)

 

by: crittoPosted on 2009-07-24 at 03:29:30ID: 31607003

thanks pal. working well.

20120131-EE-VQP-002

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