Question

XSLT Error

Asked by: FirePits

I am receiving an error when trying to transform an xml doc with the xsl below. The error message states:

xsl:template is not allowed in this position in the stylesheet!

Any help in identifying the error and a possible resolution is appreciated.

<xsl:template name="result">
 
	<div class="searchResult">
		<span class="date">
<!-- The example XML doesn't contain date fields; the values would go here, but this placeholder is here instead. -->
			<xsl:text> </xsl:text>
		</span>
		<h3>
			<xsl:choose>
				<xsl:when test="fields/field[@name='ext']/value = 'pdf'">
					<a class="pdf">
						<xsl:attribute name="href"><xsl:value-of select="reference"/></xsl:attribute>
						<xsl:value-of select="title" disable-output-escaping="yes"/>
					</a>
				</xsl:when>
				<xsl:otherwise>
					<a>
						<xsl:attribute name="href"><xsl:value-of select="reference"/></xsl:attribute>
						<xsl:value-of select="title" disable-output-escaping="yes"/>
					</a>
				</xsl:otherwise>
			</xsl:choose>
		</h3>
		<p>
						<xsl:template match="summary">
				<xsl:call-template name="globalReplace">
					<xsl:with-param name="outputString" select="summary"/>
					<xsl:with-param name="target" select="'&lt;br&gt;'"/>
					<xsl:with-param name="replacement" select="''"/>
				</xsl:call-template>
			</xsl:template>
		</p>
		<a>
			<xsl:attribute name="href"><xsl:value-of select="reference"/></xsl:attribute>
			<xsl:value-of select="reference"/>
		</a>
	</div>
</xsl:template>
 
 
<!-- Template to replace a text substring. --> 
<xsl:template name="globalReplace">
	<xsl:param name="outputString"/>
	<xsl:param name="target"/>
	<xsl:param name="replacement"/>
	<xsl:choose>
		<xsl:when test="contains($outputString,$target)">
			<xsl:value-of select=
				"concat(substring-before($outputString,$target),
				$replacement)"
				disable-output-escaping="yes"/>
			<xsl:call-template name="globalReplace">
				<xsl:with-param name="outputString" 
					select="substring-after($outputString,$target)"/>
				<xsl:with-param name="target" select="$target"/>
				<xsl:with-param name="replacement" 
					select="$replacement"/>
			</xsl:call-template>
		</xsl:when>
		<xsl:otherwise>
			<xsl:value-of select="$outputString" disable-output-escaping="yes"/>
		</xsl:otherwise>
	</xsl:choose>
</xsl:template>
 
 
<!--Template to generate a URL query string composed of parameters passed to the current search.
	 Optional parameter "exclude" is passed to exclude a specific parameter from being appended -->
<xsl:template name="paramString">
	<xsl:param name="exclude" select=""/>
	<xsl:for-each select="/searchResponse/query/param">
		<xsl:if test="$exclude != ./@name">
			<xsl:if test="position() &gt; 1">&amp;</xsl:if>
			<xsl:value-of select="concat(@name,'=',@encoded)"/>
		</xsl:if>
	</xsl:for-each>
</xsl:template>
 
 
<!--Pagination template - displays a single page number (linked unless it's the currently displayed page) and calls itself to display the next page.-->
<xsl:template name="pagination">
	<xsl:param name="min" select="1"/>
	<xsl:param name="max" select="100"/>
	<xsl:param name="pageStart" select="1"/>
	<xsl:param name="pageEnd" select="10"/>
	<xsl:param name="constResultsPerPage" select="10"/>
	<xsl:param name="pageNumber" select="1"/>
	<xsl:param name="nextPagenumber" select="1"/>
	<xsl:param name="constURL"/>
 
	<li>
		<xsl:choose>
			<xsl:when test="$pageNumber != $nextPagenumber">
				<a>
				<xsl:attribute name="href"><xsl:value-of select="$constURL"/>&amp;start=<xsl:value-of select="$min"/></xsl:attribute>
				<xsl:value-of select="$nextPagenumber"/>
				</a> 
			</xsl:when>
			<xsl:otherwise>
				<xsl:attribute name="class">active</xsl:attribute>
				<xsl:value-of select="$nextPagenumber"/> 
			</xsl:otherwise>
		</xsl:choose>
	</li>
 
	<xsl:if test="($min + $constResultsPerPage) &lt;= $max">
		<xsl:call-template name="pagination">
			<xsl:with-param name="min"><xsl:value-of select="$min + $constResultsPerPage"/></xsl:with-param>
			<xsl:with-param name="max"><xsl:value-of select="$max"/></xsl:with-param>
			<xsl:with-param name="pageEnd"><xsl:value-of select="$pageEnd"/></xsl:with-param>
			<xsl:with-param name="constResultsPerPage"><xsl:value-of select="$constResultsPerPage"/></xsl:with-param>
			<xsl:with-param name="pageNumber"><xsl:value-of select="$pageNumber"/></xsl:with-param>
			<xsl:with-param name="nextPagenumber"><xsl:value-of select="$nextPagenumber + 1"/></xsl:with-param>
			<xsl:with-param name="constURL"><xsl:value-of select="$constURL"/></xsl:with-param>
		</xsl:call-template>
	</xsl:if>
</xsl:template>

                                  
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Asked On
2009-09-03 at 16:43:46ID24706449
Tags

XSL

,

XSLT

,

XML

,

xsl:template

Topic

Extensible Stylesheet Language Transformation (XSLT)

Participating Experts
2
Points
500
Comments
5

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Answers

 

by: zc2Posted on 2009-09-03 at 16:57:36ID: 25256053

A template can not reside inside another template.
Look at the line 25 of the snippet you provided, there is <xsl:template> element, but this code around already a template!

 

by: FirePitsPosted on 2009-09-03 at 17:30:57ID: 25256154

Thank your for your help, do you know if there's a way to achieve the same result without using the nested template?

 

by: GertonePosted on 2009-09-04 at 03:02:01ID: 25258014

there is no "the same result" because a nested template will render no result.

Basically you can push out nodes (usually childnodes, but could be a more complex XPath expression)
to be evaluated by the templates.
For that you use <xsl:apply-templates...>

I think what you want to do is something like this
            <p>
                <xsl:apply-templates select="summary"/>
            </p>

Then you can have a template for summary outside the "result" template
That is where templates belong, next to each other, instead of being nested

...
           <a>
                <xsl:attribute name="href"><xsl:value-of select="reference"/></xsl:attribute>
                <xsl:value-of select="reference"/>
            </a>
        </div>
    </xsl:template>
 
    <xsl:template match="summary">
        <xsl:call-template name="globalReplace">
            <xsl:with-param name="outputString" select="."/>
            <xsl:with-param name="target" select="'<br>'"/>
            <xsl:with-param name="replacement" select="''"/>
        </xsl:call-template>
    </xsl:template>

I also removed one mor etypo from you stylesheet
    <xsl:template name="paramString">
        <xsl:param name="exclude" select="''"/>

note the two single quotes in the select, to indicate the empty string value as a default

 

by: FirePitsPosted on 2009-09-07 at 11:06:06ID: 25276499

Thank you both!

 

by: GertonePosted on 2009-09-07 at 12:05:05ID: 25276765

welcome

20120131-EE-VQP-002

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