Sandy209
asked on
Generating a random 3 digit number - Java 1.4
Hi all,
What is the cleanest way to generate a random 3 digit number in Java 1.4 ?
java.util.Random can generate 0 - 999 but doesn't seem to have anything in it's api to support generating only 3 digits.
Any suggestions?
What is the cleanest way to generate a random 3 digit number in Java 1.4 ?
java.util.Random can generate 0 - 999 but doesn't seem to have anything in it's api to support generating only 3 digits.
Any suggestions?
ASKER
Hi boing40001,
Not necessarily, it would be a more complete solution if say 001 was an option. Although for lack of a better solution it would acceptable as a last resort.
Not necessarily, it would be a more complete solution if say 001 was an option. Although for lack of a better solution it would acceptable as a last resort.
001 is the same as 1 numerically. Its only different if you want to print it/ use it as a string.
in that case stick with random
and use
String.format("%03d", randomNumber);
to make sure that it always has 3 digits
in that case stick with random
and use
String.format("%03d", randomNumber);
to make sure that it always has 3 digits
if you want codes also like 001 then why don't you generate 3 numbers in interval 0..9 and then join the three numbers ?
ASKER
@robthewolf - String.format is Java 1.5
@boing40001 - I considered that solution myself, i was just hoping for something a little less hacked :-)
@boing40001 - I considered that solution myself, i was just hoping for something a little less hacked :-)
you can use sprintf in exactly the same way in terms of formatting output. That must be available in 1.4
ASKER
what do i need to import to use sprinf(... ) ?
i really dont know if these are in 1.4 or not but try either
http://java.sun.com/j2se/1.5.0/docs/api/java/util/Formatter.html
or
System.out.printf();
http://java.sun.com/j2se/1.5.0/docs/api/java/util/Formatter.html
or
System.out.printf();
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ASKER
I think this is a clean as we can expect in Java 1.4
just add a check on the generated number by java.util.Random and, if lower than 100, generate a new number