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RichTextBox.Find method strt/end integer arguments

Posted on 1997-04-03
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Last Modified: 2012-08-13
How do I get around the RichTextBox.Find methods integer start argument when I want to find a string with the cursor being past the 32k mark? I am using this with a 'find' and a 'find next' type menu command. (like in all text editors)
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Question by:cristopher
3 Comments
 
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Expert Comment

by:YiannisVolos
ID: 1425028
Hello i am YiannisVolos. My answer for your question. I designed a special code for making FindNext(Find). It makes the same work. If you want you can change the given code, if you make changes which make it more powerful please e-mail it to me. Thank you.

In your button click paste the following source code.(the code is visual basic).
-S-T-E-P-S------------------------------------------------------------------------------------
a) add a textbox on a form.
b) add a command button
c) and a RichTextBox that it will contain the text of your user
---------------------------
StartFind:
If TextBox.Text <> "" Then
FoundPosition = InStr(Start + 1, UCase$(HomeEditor.richtextbox1.Text), LCase$(TextBox.Text))
If FoundPosition <> 0 Then
richtextbox1.SelStart = FoundPosition - 1
richtextbox1.SelLength = Len(TextBox.Text)
Start = FoundPosition
Else


If TestTimes = 1 Then
Response = MsgBox("Your program could not find the given text.", 0, "Your program title - Error Message")
Start = 0
Else
Start = 0
TestTimes = 1
GoTo StartFind
End If
End If
End If








my email: volosm@cytanet.com.cy
please increase the award points
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Author Comment

by:cristopher
ID: 1425029
Your solution is the same as mine. It will not work over 32k. Could it be that the SelLength and SelStart properties of the RichtextBox are integers also?
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Accepted Solution

by:
thalem earned 200 total points
ID: 1425030
Use Long instead of integer. I've done it, and it works well.
There is therefore no 32k limitation. Yeap. It's that simple.

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