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using Setbkcolor???

Posted on 1997-04-03
Medium Priority
Last Modified: 2012-05-04
How do I use the setbkcolor API for a textbox by passing a window handle?
This is what I am doing:
1.declaring the setbkcolor and getDC  API's at the module level.
2.At a form load, I pass the handle (hWnd) of my textbox to the GetDC API, to convert the hWnd handle to a hDC as follows:
l = getDC(text.hWnd) (BTW, l is a global long variable)
3. I call SetBkColor API as follows:
setBkcolor(l, RGB(255,0,0): this returns the value 255 meaning the code is being executed; but does not change the backcolor of my textbox to Red as it is supposed to.
What may be wrong??
Stepwise Suggestions welcome!!
Question by:schhaya
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Expert Comment

ID: 1425032
Why is the getDC in the form load? Wouldnt it be better to put it next to the setbkcolor api call? Storing hdc's in variables for a period of time is generally frowned upon becuase they may change... Especially since you are doing this in the form load, your returned hdc may not be what you expect.

It is also worth splitting out the rgb function (and maybe the text.hwnd) from the api call and assigning it to long instead. VB can do some strange things with parameters as functions.


Author Comment

ID: 1425033
The getDC(hwnd) API returns the hDC of the object whose hWnd is passed as an argument to the API. The windowfromDC(hDC) API gives back the hWnd from the hDC. When I verify the hWnd  using the WindowfromDC, it returns the exact same hWnd of the object as before. Therefore, I dont think the hDC is changing due to which the setBkcolor is not carried out. Anyways, I tried out your suggestion and put the GetDC in the immediately previous step to calling the SetBkcolor API. Still no result. As I said before, the code itself is being executed; it returns the value of 255 (which is the long value of the color Red); but does not set the backcolor of the object to Red.

Expert Comment

ID: 1425034
I suppose that you wish to change the backcolor right? Like the property of the Text1.Backcolor.
Well you ought to know that API func. SetBkColor isn't supposed to set the background color property like the func. names describes. I think. The describtion for the func. is this: Sets the background color for the specified device context. The background color is used to fill the gaps in hatched brushses, dashed pens, and characters if the background mode is OPAQUE. It is also used during bitmap color conversions.
So I think by the describtion of the function it's not supposed to.

Author Comment

ID: 1425035


Accepted Solution

Lucas041697 earned 300 total points
ID: 1425036
The information in this article applies to:

 - Microsoft Windows Software Development Kit (SDK) for Windows
   versions 3.1 and 3.0

 - Microsoft Win32 Application Programming Interface (API) included with:

    - Microsoft Windows NT versions 3.5 and 3.51
    - Microsoft Windows 95 version 4.0

The syntax for the SetBkColor function is documented in the Microsoft Windows Software Development Kit (SDK) as follows:

   DWORD SetBkColor(HDC hDC, COLORREF crColor);

SetBkColor sets the current background color of the specified device context (DC) to the color that the crColor parameter references, or to the nearest physical color if the device cannot represent the RGB color value that the crColor parameter specifies. In other words, SetBkColor cannot be used to set the background to a dithered color and defaults to the physical color that is closest to the requested crColor value.

This behavior can cause unexpected results for an application that changes the background color of a control to a color that cannot be represented by a color provided by the display device.
Specifically, when an application specifies a dithered color for the background of an edit control, and specifies the same color for the text background, Windows paints the control in two distinct colors.
For example, using the standard VGA display driver, the following call, in which COLOR_INACTIVEBORDER is a green/gray specified by RGB(64, 128, 128), sets the background color to gray (RGB(128, 128, 128)) rather than the dithered green/gray that is desired:

   SetBkColor(wParam, GetSysColor(COLOR_INACTIVEBORDER));

To illustrate, if the application uses the function call while

processing the WM_CTLCOLOR message to change the color of an edit control, the window background is painted green/gray, and the text background defaults to the nearest physical color, which is gray. This produces a gray rectangle inside a green/gray rectangle rather than the desired green/gray for the entire edit control.
This behavior can also occur with other controls such as option buttons and list boxes. However, an application can avoid this problem by using the SetBkMode function to set the background mode to TRANSPARENT. This allows the dithered brush pattern to show through beneath the text to achieve the desired results. That solution is not practical with a multiline edit control because if text is inserted, and the background mode has been set to TRANSPARENT, the text that is pushed to the right by the inserted text leaves its image behind. The result is text superimposed on top of other text, which quickly becomes unreadable.
To partially work around this situation for a multiline edit control, use the GetNearestColor function to determine the nearest physical color to the desired color, as in the code fragment below. In this case, the entire edit control is gray:

   case WM_CREATE:
      HDC hDC;
      hDC = GetDC(hWnd);
      hGrayBrush = CreateSolidBrush(GetNearestColor(hDC,
            RGB(64, 128, 128)));
      ReleaseDC(hWnd, hDC);
      hWndEdit = CreateWindow( ... ES_MULTILINE ... );

   case WM_CTLCOLOR:
      if (HIWORD(lParam) == CTLCOLOR_EDIT)
         // The following call creates the nearest physical
         // color; therefore, it will be the same as the
         // hGrayBrush created above.
         SetBkColor(wParam, RGB(64, 128, 128));
         SetTextColor(wParam, RGB(255, 0, 0)); // red text
         return (DWORD)hGrayBrush;
        return DefWindowProc(hWnd, identifier, wParam, lParam);


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