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Help with Perl and removing info from a ypcat

Posted on 1997-04-03
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Last Modified: 2013-12-26
I want to find where each users home account is.. I am doing
a:

      #!/serve/bin/perl -w
        open(USERS, "user_list") || die "could not open file ($!)";
        while(<USERS>) {
            $person="$_";      
            $local = `ypcat passwd | grep $person`;
            print $local;
        }    

I want to remove the exta info that the ypcat gives me.  I tried doing
a $local =~ s/^$person//g; to start widdling away at the output of $person
but it doesn't work.

Any suggestions?

-Allen
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Question by:allenm040397
1 Comment
 

Accepted Solution

by:
trip040397 earned 200 total points
ID: 1292497
The answer is not to use ypcat. Use getpwnam() which returns an array, one element of which is the user's home dir. Exactly which element depends on the password file format. Grepping the passwd file like this is dangerous because, for instance, user pete and petew would both pass the grep for user pete.

You dont say which flavour of unix you are using and it is possible that getpwnam() is not available on your system in which case use:

open(PW, "passwd");
while (<PW>) {
  if (/^$person\:/) {
    @pwent = split (/:/);
  }
}

$home_dir = $pwent[4]

... it may not be item 4, depends on your passwd file format.

steve

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