9628657
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help (urgent)
I have a little problem concerning arrays.
Say I have an array called Numbers and it has 10 elements :
array pointer contents
0 3
1 8
2 12
3 66
4 7
5 128
6 1001
7 45
8 63
9 1137
To access for example the third elemnt in the array, I have to write, cout << Numbers[2] << endl ;
and that would print 12.
But if I had two variables, x = 1 and y = 2 then typing, cout << Numbers[x+y] does not print 12, instead it prints 3.
Does anyone know why that is, and how can I correct this so that it prints the contents instead.
Cheers.
My email address is :
a.Al-allak@uea.ac.uk
Say I have an array called Numbers and it has 10 elements :
array pointer contents
0 3
1 8
2 12
3 66
4 7
5 128
6 1001
7 45
8 63
9 1137
To access for example the third elemnt in the array, I have to write, cout << Numbers[2] << endl ;
and that would print 12.
But if I had two variables, x = 1 and y = 2 then typing, cout << Numbers[x+y] does not print 12, instead it prints 3.
Does anyone know why that is, and how can I correct this so that it prints the contents instead.
Cheers.
My email address is :
a.Al-allak@uea.ac.uk
Could use some source code. Is x and y an int? how are you defining x and y?
ASKER
Yes, x and y are defined as integers.
The way you discribe it there should be no problem... Can you post more of your code?
Philippe
What compiler do you use?
It is not possible to find error in your code until you post this code!
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The problem you posted is NOT normal (as jmmougeolle said). In fact, x+y = 3, and therefore Numbers[x+y] should give 66, not 12 as you're expecting. But I'd recommend posting most of your program, so that I may be able to find the actual error.
jmmougeolle said:
>That's normal you got that result...
>Your X+Y value give a result of 3 So Numbers[3] is exactely 3!
>What you want to have as a X+Y result is 2!!! Not 3! SO >Numbers[2] will give you 12, and that's what you are expecting!
>In fact, the error come from the 0 based organisation of your >coordinate!
I do not believe this answer to be correct for the following reason: If you want x+y to give you the answer 2 so the number 12 will be displayed, why was 66 not displayed when x+y summed to 3? 66 is the value in element 3 of the array and that is what should have been displayed if jmmougeolle's theory is correct. Just a thought....no offense is intended.
>That's normal you got that result...
>Your X+Y value give a result of 3 So Numbers[3] is exactely 3!
>What you want to have as a X+Y result is 2!!! Not 3! SO >Numbers[2] will give you 12, and that's what you are expecting!
>In fact, the error come from the 0 based organisation of your >coordinate!
I do not believe this answer to be correct for the following reason: If you want x+y to give you the answer 2 so the number 12 will be displayed, why was 66 not displayed when x+y summed to 3? 66 is the value in element 3 of the array and that is what should have been displayed if jmmougeolle's theory is correct. Just a thought....no offense is intended.