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Displaying Long Double

samtan
samtan asked
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Last Modified: 2008-03-10
I've declared a long double variable and tried to display it but could only display in exponential format.

The problem is, C allows me to declare a long double but printf and sprintf only handles up to the size of double (16 digits).

I need to at display the full value on the screen as well as converting it to a string using sprintf. To illustrate:

/* Dummy codes */
long double buf1, buf2, result;
char ans[20];

buf1 = 12345678901234567.00;
buf2 = 12345678901234567.00;
result = buf1+buf2;
printf("result: %17.0f", result);
sprintf(ans, "%17.0f", result);

If printf and sprintf can't work please suggest other alternatives.

Note: The maximum length of the variable "result" can go up to 18 digits.

Please help, this is urgent. Thank you.
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(1) Long double is not ANSI C. It is an extension.
(2) On my machine I can only get 17 significant figues for long double. You may be asking for more than is available.
(3) Are you only using whole numbers? If so:
(3.1) consider looking at one of the multiple-precision-integer packages that are around.
(3.2) consider using "long long integer" which gcc (at least) supports.
Both of these enable you to use 64 bit integers, which give up to 20 decimal digits. (If you are on a Digital Alpha they are native).
Commented:
Try to use "fcvt" function. Prototype is in "stdlib.h".

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prc

Commented:
No, fcvt takes a double argument.

You can use (s)printf in some systems.  It's not part of the ANSI spec for (s)printf though.  In GNU library systems (including Linux), you can use the 'L' prefix (yes, upper case).  In BSD, you can use 'q'.  Actually, you can use 'q' in both, so that's the more portable (but not Portable) way of doing it.

The follow code works fine on Linux:

#include <stdio.h>

int main()
{
  long double a,b,c;
  a=12345678901234567.00;
  b=12345678901234567.00;
  c=a+b;
  printf("result: %17.0qf\n", c);  /* Or Lf */
  return 0;
}

If this is any good to you, reject the above and I'll enter an empty answer for you to accept.

Cheers

Paul
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