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# Hexa to float, how to?

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I need to convert some hexadecimal code to float or double, how can I achive this?
ex:
I have in the code   2A ED 00 F2
what is the equivalent in a float number?
or double?
Is there any functiuon in C that performs this action?
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Commented:
Assuming that the input characters are all upper case HEX digits, this should do the job of getting each byte into an int.
Then you can merge them together by just multiplies of 256.

float f;
f = byte2int( "2A");
f = 256 * f + byte2int( "ED");
f = 256 * f + byte2int( "00");
f = 256 * f + byte2int( "F2");

There is a tacit assumption here that the number that you are passing in is not stored in an odd way. If it is stored in memory as a float, than this will not work. Also, the above code might be exactly opposite of what you want, depending on the byte ordering of your architecture. Try it on a number that you know to verify the ordering.
int byte2int( char in[3]) /* 2 bytes and a null */
{
int i;
i = 16 * (( in[0] > '9') ? in[0] - 'A' : in[0] - '0');
i += (( in[1] > '9') ? in[1] - 'A' : in[1] - '0');
return( i);
}

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Commented:
Thanks very much for your support mr.emmons!
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