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TFTP without form

Posted on 1997-05-15
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Last Modified: 2012-05-04
I encounter problems with the TFTP component:
I'm working under delphi 2.0 Client/Server, writing a console application
using the TFTP component (as an object created in the application).
Since now I never managed to even connect to my FTP server,
but by hazard, I saw that puting a messagebox call at the end of my code make
it work perfectly. I try to replace it by a sleep and so on, no one made it.
Here is my code :

program ftpsrv;

uses
  SysUtils,
  Classes,
  Windows,
  WinSvc,
  NTObj,
  SvcObj,
  DB,
  ISP,Dialogs,
  DBTables,ExtCtrls;

type TFTPc=class(TFTP)
     procedure FTPProtocolStateChanged(Sender: TObject; ProtocolState: Smallint);
end;

{$R *.RES}
var ftpc : TFTPc;
    compteur : integer;
   
{******** this event protocolstatechanged is
never called if i don't put the messagebox you'll see next **************}
procedure TFTPc.FTPProtocolStateChanged(Sender: TObject; ProtocolState: Smallint);
begin
  case ProtocolState of
    ftpBase : ftpc.Free;
    ftpAuthentication: Authenticate(UserId, Password);
    ftpTransaction: begin
                  {****** when connected I get a file to see if it works}        
            ftpc.GetFile('./docserveurNT4.htm','c:\essai.htm');
                    end;
  end;
end;

begin
{******* create the object}
ftpc:=TFTPc.Create(Nil);
{******* attach the procedure to the event}
ftpc.OnProtocolStateChanged := ftpc.FTPprotocolStateChanged;

ftpc.Password:='3il@hol.fr';
ftpc.RemoteHost:='192.9.200.2';
ftpc.RemotePort:=21;
ftpc.UserId:='anonymous';
ftpc.Connect(ftpc.remoteHost,ftpc.RemotePort);
{????????????????   here is the messagebox ?????????????}
MessageDLG('test',mtinformation,[mbOK],0);
{???????????????? if i don't put this, my file isn't downloaded, just because the
FTP client never connects. the event protocolstatechanged is never called

Please help me !!!!! 8°)
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Comment
Question by:apostoly
  • 5
6 Comments
 

Expert Comment

by:chrb
ID: 1336284
Hi!

>ftpc:=TFTPc.Create(Nil);
Try this :
 ftpc:=TFTPc.Create(Application);

If it dosn't work try something like this :
 ftpc:=TFTPc.Create([Name of your form]);

Good luck :)

Chr
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Author Comment

by:apostoly
ID: 1336285
not good answer the question is without a Form nor a TApplication
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Expert Comment

by:chrb
ID: 1336286
Sorry,
0
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Expert Comment

by:chrb
ID: 1336287
Sorry.
0
 

Accepted Solution

by:
chrb earned 0 total points
ID: 1336288
Now I tried it in Delphi, didn't do that last time. But now it works :)

This work fine with me :

program ftpsrv;

uses
 SysUtils,
 Classes,
 Windows,
{ WinSvc,
 NTObj,
 SvcObj,}  { I Havn't client/server}
 DB,
 ISP,Dialogs,
 DBTables,ExtCtrls;

type TFTPc=class(TFTP)
 procedure FTPProtocolStateChanged(Sender: TObject; ProtocolState: Smallint);
end;

var ftpc : TFTPc;
 compteur : integer;
 
{******** this event protocolstatechanged is
never called if i don't put the messagebox you'll see next **************}
procedure TFTPc.FTPProtocolStateChanged(Sender: TObject; ProtocolState: Smallint);
begin
 case ProtocolState of
 ftpBase : ftpc.Free;
 ftpAuthentication: Authenticate(UserId, Password);
 ftpTransaction: begin
 {****** when connected I get a file to see if it works}
ftpc.GetFile('/w95files/patch/tray.zip','c:\tray.zip');
 end;
 end;
end;

begin
{******* create the object}
ftpc:=TFTPc.Create(ftpc);
{******* attach the procedure to the event}
ftpc.OnProtocolStateChanged := ftpc.FTPprotocolStateChanged;

ftpc.Password:='lboehn@online.no';
ftpc.RemoteHost:='www.sentralen.com';
ftpc.RemotePort:=21;
ftpc.UserId:='anonymous';
ftpc.Connect(ftpc.remoteHost,ftpc.RemotePort);
{???????????????? here is the messagebox ?????????????}
MessageDLG('test',mtinformation,[mbOK],0);
end.

Hope you get it working now :-)
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Expert Comment

by:chrb
ID: 1336289
Did it works?
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