Solved

how do i reset a setTimeout?¿

Posted on 1997-05-29
4
1,050 Views
Last Modified: 2006-11-17
Can someone look over this and  tell me why its not working.
What I want it to do is to jump to another page after no activity for 5
minutes.  I want to turn the whole page into an image map so when the
mouse moves off an image it resets the timer. Please help!
heres what ive got so far:

<HTML>
<HEAD>
<TITLE>
</TITLE>

<SCRIPT LANGUAGE="JavaScript">
<!--hide me
self.name="only"
function goNext() {
open("timer2.html", "only");
}

function reSet() {
clearTimeout(myTimer);
}
//stop hiding-->
</script>
</head>
<body onLoad="myTimer= setTimeout('goNext()',5000)"><!---this is the
time in miliseconds-->

your image map or pictures go here,
be sure to have the "onMouseout" thing within the image tag

<img src="color_cube_colors.gif" onMouseout="reSet; goNext();">
<img src="color_cube_colors.gif" onMouseout="reSet; goNext();">
<img src="color_cube_colors.gif" onMouseout="reSet; goNext();">

</body>
</html>

THANKS
danny   mailto:impulse@usa.net

0
Comment
Question by:wired
  • 2
4 Comments
 

Expert Comment

by:gbingers
ID: 1265923
Did you try: onMouseOut="(reSet();goNext();)"

note the parentheses after reSet.
0
 

Author Comment

by:wired
ID: 1265924
thank you for trying, but that didnt work...please keep helping!
0
 
LVL 3

Accepted Solution

by:
garik earned 50 total points
ID: 1265925
First, let's change reSet() function - it should set a new timeout after clearing a previous one:

 function reSet() {
clearTimeout(myTimer);
myTimer = setTimeout('goNext()',5000);
}

Next, onMouseOut and onMouseOver events are generated only for the Link object; therefore, either make those images real image maps or put them inside the anchor:

<A HREF=/ onMouseOver='reSet()' onMouseOut='reSet()'>
    <IMG SRC='some.gif'>
</A>

I'd suggest to use both events to detect activity. In addition, onMouseOut has been introduced only in Netscape 3.0, so previous Netscape and MS IE dosn't understand it.

I hope I understood your problem correctly; if not, please comment on the answer before rejecting it :)

Cheers
0
 

Author Comment

by:wired
ID: 1265926
THANK you very much, that worked perfectly! u rock!
0

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