# numeric representation/precision error

I am relatively new to the java programming world, and having a really annoying problem with this piece of code:

import java.io.*;

class doubleTest {
public static void main(String argv[]) {
double sigDigits = 9.74;
double shiftLeft = 9.0;  // number of places to                                         shift decimal left

for (int i = 1; i <= shiftLeft; i++) {
sigDigits = sigDigits/10.0;
System.out.println(sigDigits);
}
}
}

this produces the following output:
0.974
0.0974
0.00974
9.74E-4
9.740000000000001E-5
9.740000000000002E-6
9.740000000000001E-7
9.740000000000001E-8
9.740000000000002E-9  // I get this number also if I                                  substitute for loop with:
sigDigits = Math.pow(sigDigits,-shiftLeft);

Why the extra digit at the end of the number?  Is there a better way to divide doubles that don't produce erroneous output?  If you change shiftLeft to 19.0,
you get the following output:
0.974
0.0974
0.00974
9.74E-4
9.740000000000001E-5
9.740000000000002E-6
9.740000000000001E-7
9.740000000000001E-8
9.740000000000002E-9
9.740000000000002E-10
9.740000000000002E-11
9.740000000000002E-12
9.74E-13
9.740000000000001E-14
9.740000000000001E-15
9.74E-16
9.74E-17
9.74E-18
9.74E-19

this is very strange to me.  Thanks in advance for you help.
-Matt
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Commented:
All floating point libraries introduce presition errors, the good ones simply produce them less often. Unfortunatley Java's FP lib is not amongst the best.

There are 3 possible work arrounds:

1.- If the error affect your results somhow, you will have to use native methods. See:

http://www.inf.uni-hohenheim.de/top/java/tutorial/native1.1/index.html

on how to use them.

2.- If the error only affects your results for display purposes (I.e.: the accumulated effect of the errors does not affect the values you wish to display), use formatting classes on the  output to get rid of the error. See:

http://www.acme.com/java/software/Acme.Fmt.html

for a class that will allow you to do this.
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