Posting a form without changing the current HTML page.

My Perl script executes UNIX shell commands by system(), exec() or open(). The browser always shows the result of the commands. Can I do something to "cover" this result (by printing a HTML) or simply do not return data to the browser (the page doesn't change in the browser)?
kenyscAsked:
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pc012197Commented:
The unix shell commands print their output to stdout and stderr. The server takes that output and includes it into the page created by the script.
The solution to your problem is to redefine stdout and stderr before invoking the shell commands:

open(SAVEOUT, ">&STDOUT");
open(SAVEERR, ">&STDERR");
open(STDOUT, ">foo.out") || die "Can't redirect stdout";
open(STDERR, ">&STDOUT") || die "Can't dup stdout";

# your unix commands go here...

close(STDOUT);
close(STDERR);

open(STDOUT, ">&SAVEOUT");
open(STDERR, ">&SAVEERR");

See also the perlfunc manpage for the open() function.

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ozoCommented:
You can also grab the STDOUT of commands with
      $outputfromcommand = `command`;
instead of
      $exitvalueofcommand = system("command");

See the perlop manpage for the qx operator
(or if you really want to cover it in HTML, I suppose you could
wrap it in an HTML comment...)


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