Getting the long filename

Posted on 1997-10-02
Last Modified: 2010-04-04
How do I get the long filename for a given short ? (c:\progr~1 -> c:\Program Files).
The Explorer's "Send to"-Menu gives only the short name for a selected file/directory. How do I convert it.
Maybe you use SHGetLongFileName or GetLongFileName.
Please send me an example !

Thank you !
Question by:webers
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Accepted Solution

ZifNab earned 10 total points
ID: 1346754
Hi webers,

The examples are not from me, but I think this is what you need.

From: "DynaSoft." <>

Function GetShortFileName(Const FileName : String) : String;
  aTmp: array[0..255] of char;
  if GetShortPathName(PChar(FileName),aTmp,Sizeof(aTmp)-1)=0 then
     Result:= FileName

Function GetLongFileName(Const FileName : String) : String;
  aInfo: TSHFileInfo;
  if SHGetFileInfo(PChar(FileName),0,aInfo,Sizeof(aInfo),SHGFI_DISPLAYNAME)<>0 then
     Result:= String(aInfo.szDisplayName)
     Result:= FileName;

Have fun,
c.u. ZifNab;

Author Comment

ID: 1346755
I haven't tested yte, but I think it'll work.

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