LoadFromFile in C++ Builder

In my program i try to load several Bitmaps while the program is running. In Delphi 2.0 exists the method
LoadFromFile. Using this method the following code works
Image1.Picture.LoadFromFile('C:\pictures\example.bmp');.
The analogous code using the -> operator instead of the . operator doesn't work. Who can me post an exmple using this
method in Borland C++ builder environment. Thank you
yours Thorsten
thorstenAsked:
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cphCommented:
To load a bitmap into an image control's picture pass the name of a bitmap file to the picture's LoadFromFile method:

void __fastcall TForm1::FormCreate(TObject *Sender)
{
   Image1->Picture->LoadFromFile("c:\\windows\\athena.bmp");
}

The picture recognizes .BMP as the standard extension for bitmap files, so it creates its graphic as a TBitmap, then calls that graphic's LoadFromFile method. Because the graphic is a bitmap, it loads the image from the file as a bitmap.

Hope this help,

CpH
0

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cphCommented:
Oupps... here is the complete source file :-)

//---------------------------------------------------------------
#include <vcl\vcl.h>
#pragma hdrstop

#include "Unit1.h"
//---------------------------------------------------------------
#pragma resource "*.dfm"
TForm1 *Form1;
//---------------------------------------------------------------
__fastcall TForm1::TForm1(TComponent* Owner)
      : TForm(Owner)
{
}
//---------------------------------------------------------------

void __fastcall TForm1::FormCreate(TObject *Sender)
{
   Image1->Picture->LoadFromFile("c:\\windows\\athena.bmp");
}
//---------------------------------------------------------------

Sorry about this,
CpH
0
thorstenAuthor Commented:
Hallo cph!
Thank you for your answer. But I wonder why I have to use the double backslash. Why is this not written  in the help file.
Yours Thorsten.  
0
maggcCommented:
Double backslash must be used because the single backslash is a special escape character. It is not accepted.

The double backslash is in fact only 1 byte of code!

char c;
c = '\\'; // works! a character can take only 1 byte

So:

c:\1.txt  --> c:\\1.txt   (in your code)

\\server\share\1.txt  --> \\\\server\\share\\1.txt
0
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