Memory places in a unit aren't the same as whole program

If I make a unit

ex. --------------------
unit myunit;
interface
uses crt;
var a:string;
procedure myprocedure;
implementation
procedure myprocedure;
begin clrscr;
     writeln('What is a? ');
       readln(a);
       end;
end.
---------------------------
And I use this unit in this program
---------------------------
program myprogram;
uses crt,myunit;
var a:string;
begin myprocedure;
        writeln(a);readln;
end.
---------------------------
If I run this program, everything is alright, except from the (a). What does I have to do that the a is the same in the unit as in the real program???
Thanks.

mar.bol@skynet.be

babbelaarAsked:
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babbelaarAuthor Commented:
My English is not very good as you see, sorry for it.
0
mitchell042997Commented:
The reason why that does't work is because the variable a in your unit is local.  Even if this wasn't in a unit, and you did this:

procedure my_proc;
var a:string;
begin
  readln(string);
end;

begin
  my_proc;
  writeln(a);
end.

it would crap out.  To fix your problem you can do one of two things.  Moving your variable a above the interface line in your unit (i.e.:

unit my_unit;
uses crt;
var a:string;

interface
... blah ...

is one way of fixing it.  It is the poor way of fixing it, because fit makes the variable global, and that is bad.  Might as well be writing in BASIC and using gotos.  The *better* way to solve the problem is to pass the variable to the procedure:

procedure my_proc(var a:string);
begin
  readln(a);
end;

will do the trick.  The var is important, because it passes the parameter by reference rather than by value.  I would highly recommend reading up on the differences between passing by reference and value.

Hope this solves your particular problem!  :)
0

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babbelaarAuthor Commented:
If I do it I receive error 55: Interface expected.
The program needs on the second line after unit(.....);
interface.

What am I doing wrong???
0
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mitchell042997Commented:
OK, I see what is wrong now.  I was incorrect when I said to move it above the interface line.  If it is below the interface but before the implementation, then it is global.  What you need to do is NOT to declare:

   var a:string;

in your main program.  Since a is already declared in your unit, you need not declare it again.  (Hence an argument against global variables).  So, if you modify your main program to look like this:

uses crt,myunit;
begin
  myprocedure;
  writeln(a);
end.

It will work beautifully.  Again, I would recommend solving this problem using other techniques, but this should provide an adequate solution for your current problem...  :)
0
mitchell042997Commented:
OK, I see what is wrong now.  I was incorrect when I said to move it above the interface line.  If it is below the interface but before the implementation, then it is global.  What you need to do is NOT to declare:

   var a:string;

in your main program.  Since a is already declared in your unit, you need not declare it again.  (Hence an argument against global variables).  So, if you modify your main program to look like this:

uses crt,myunit;
begin
  myprocedure;
  writeln(a);
end.

It will work beautifully.  Again, I would recommend solving this problem using other techniques, but this should provide an adequate solution for your current problem...  :)
0
babbelaarAuthor Commented:
I'll try tomorrow because my mother says that I have to go to my bed.
It 22.10pm and I live in Belgium.16/m
0
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