asked on

Help : Cannot understand error mesg.

Hello,
I have written a C program to build the tables
that an assembler usually does. After compiling and trying
to run the program, an error message is displayed :

General Protection Exception
0xf8DF:0x0D12
SYS1A(1) 0x58DF:0X0D12 Processor Fault

I would really appreciate it if someone could tell me
whats going on ? What kind of error message is this and
where do I need to look ? The message gives me no idea of
where do I start looking for a problem.
I will summarize.

Waiting for a response.
Thanks.
Jeetandra

ASKER CERTIFIED SOLUTION

Jackie071497

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jmahtani

ASKER

Hello,
Thanks for replying. I believe the error is being caused due to an array that is of 68 by 48. When I cut the array size from 68 by 48 to 37 by 48( and commented the rest), I did not get the error. Then I decided to cut the 68 by 48 array to two arrays - 37 by 48 and 31 by 48, but then the error message came back. Do you have any idea of whats going wrong ?
( Note : In one of the initialisations of my array, I have one of the rows as
" DC C'BANANA , ,KIWI '",
Can this be causing the problem.

If its not a problem to you, should I email my program to you, so that it will give you a better idea of how the array is being initialised.
)
Waiting for your response.
Jeetandra.

cph

You should post the part causing problem as it could be different reason like you access a memory allocation where you shouldn't or you try to free a pointer which point anywhere....

CpH

Jackie071497

You can e-mail me : sigmafei@ms1.hinet.net

But I think your better way is to post up some parts of your
initializations here. Maybe other friends also feel interested
for your coding problems.

jmahtani

ASKER

Hello,
I really appreciate your help. The following is the declaration of the array that I believe is causing the problem,since when I reduced the size of the array from 68 rows to 37, the error disappeared. When I split the 68 rows array into 2 arrays of 37 and 31 rows, the error came back. If its not a problem,, can someone please examine it and let me know of what could be causing the problem.
Waiting for your response.
Jeetandra
char code[68][48]=
{"DIFF CSECT                    ",
" STM 14,12,12(13)        ",
" BALR 12,0        ",
" USING *,12        ",
" ST 13,MAINSAV+4               ",
" LA 13,MAINSAV        ",
" LA 2,TABLE1        ",
" LA 3,TABLE2        ",
" LA 4,0        ",
"NEXT CLI 0(2),C' '        ",
" BC B'1000',GETNEXT        ",
" CLC 0(10,2),=CL10'NOMORE'        ",
" BC B'1000',NOMORE ",
" MVC 0(10,3),0(2)        ",
" LA 4,1(4)        ",
" LA 3,10(3)        ",
"GETNEXT LA 2,10(2) ",
" BC B'1111',NEXT ",
"NOMORE ST 4,COUNT ",
" LA 1,=A(PARMLT) ",
" LA 15,SORT ",
" BALR 14,15        ",
" L 13,MAINSAVE+4        ",
" LM 14,12,12(13)        ",
" R 14        ",
" LTORG ",
"PARMLT DC A(TABLE2)        ",
" DC X'80',AL3(COUNT)        ",
"MAINSAVE DS 18F        ",
"COUNT DS F ",
"TABLE1 DC C'APPLE ,PEAR , '",
" DC C'BANANA , ,KIWI '",
" DC C' ,RAMBUTAN ,DATE '",
" DC C'GRAPE ,BERRY ,DURIAN '",
" DC C'KUMQUAT ,POMEGRANIT ,PAPAYA '",
" DC C'QUINCE , ,NOMORE '",
"TABLE2 DS 15CL10                    ",
"SORT CSECT                         ",
"       STM 14,12,12(13) ",
" BALR 12,0                         ",
" USING *,12 ",
" ST 13,SORTSAVE+4               ",
"       LA 13,SORTSAVE                    ",
"        L 2,4(1)                    ",
"        L 2,0(2)                    ",
" L 5,0(2)                    ",
" BCTR 2,0                         ",
"DO10 EQU *                         ",
"       LR 3,2                         ",
" SR 4,4                         ",
"DO20 EQU *                         ",
"       L 6,0(4,5)                    ",
"IF30 C 6,10(6)                    ",
" BNH FI30                         ",
" MVC TEMP(10),10(6)        ",
" MVC 10(10,6),0(6)                    ",
" MVC 0(10,6),TEMP                    ",
"FI30 EQU *                         ",
" LA 4,10(4)                    ",
" BCT 3,DO20                    ",
"0D20 EQU *                         ",
" BCT 2,DO10        ",
"0D10 EQU *        ",
" L 13,SORTSAVE+4                    ",
" LM 14,12,12,(13)                    ",
" BR 14 ",
"TEMP DS CL10                    ",
" END DIFF                         "};

wpinto

Make sure that you are not trying to access code[68] anywhere in your program. Since 'C' language is zero based valid values are code[0] to code[67].

for(i=0; i<=68; i++) is wrong; it should be for(i=0; i<68; i++)

jmahtani

ASKER

I am not trying to access row 68 anywhere in my program. The error seems to be associated with the declaration of the array since when I reduced the array size from 68 rows to 37 rows, I did not get the error message. So I decided to split the original array of 68 rows into two arrays of 37 rows and 31 rows, but then the error message came back, which is surprising.
Waiting for a response.
Jeetandra.

Jackie071497

I felt strange in your dim declaration : char code[68][48]= ...
Your data type is only 68 "pointers", so you need to define : char *code[68]=...

Could you show us how do you accessing code[n]?

jmahtani

ASKER

Dear Jackie and everyone who helped,
Thank you very much.
char *code[68]=.... solved the problem.
Though the problem has been solved, can someone please
explain why char code[68][48] did not work, but
char *code[68]=.. worked. I was under the impression
that since my array consists of 68 rows and each row
consists of 48 columns, shouldn't char code[68][48]=...
work ??
Jeetandra

Jackie071497

*a = "1", a is a pointer. ( maybe 4 byte )
a = '1', a is a character buffer. ( 1 byte )

If you want to define code[68][48], you should use :
code[68][48] =
{ {'D','I','F','F',...}
{'S','T','M',...}
...
}