?
Solved

Access to private members by descendant classes

Posted on 1997-11-18
6
Medium Priority
?
179 Views
Last Modified: 2010-04-10
Suppose you have a certain class which has an attribute you want to maintain as private :

class A {

   private:

   int Example_Int;

   public:

   ...
};

Then you have a class which derives from the previous one, which has a certain member function.

class B : A {

   public:

   int Example_Function();
};

The member function just defined wants to have access to Example_Int without having to define it again on the derived class and without having to put it as public.

int B::Example_Function() {

   return Example_Int;           //Error
};


How to do it ?
0
Comment
Question by:sagitarian
[X]
Welcome to Experts Exchange

Add your voice to the tech community where 5M+ people just like you are talking about what matters.

  • Help others & share knowledge
  • Earn cash & points
  • Learn & ask questions
  • 3
  • 2
6 Comments
 
LVL 2

Accepted Solution

by:
rigansen earned 100 total points
ID: 1173486
Have you tried this:

class B : public A {
public:
   int Example_Function();
};

not completly sure, but maybe... if not leave a comment.


0
 
LVL 2

Expert Comment

by:rigansen
ID: 1173487
seems that the fist try didn't work...

After some testing I think you have only two possibilities:

(1)

class A {
friend class B;
private:
   int Example_Int;
};



(2)

class A {
protected:
   int Example_Int;
};



the choice is up to you...

regards.

    rigansen.
0
 
LVL 22

Expert Comment

by:nietod
ID: 1173488
Protected is the way to go.  That is what protected is for.
0
VIDEO: THE CONCERTO CLOUD FOR HEALTHCARE

Modern healthcare requires a modern cloud. View this brief video to understand how the Concerto Cloud for Healthcare can help your organization.

 

Author Comment

by:sagitarian
ID: 1173489
Even using the public specifier for class A access on class B, it still depends wether class A's attribute you use is public or not. Nevertheless, one should use class A as public or else none of the class member could be seen.

The protected solution is the best one. This way it works, which is the main purpose, but also is more understandable.

Thanks for the answers.
0
 
LVL 2

Expert Comment

by:rigansen
ID: 1173490
Could someone explain ??

My answer was graded with a *D*  :(

Maybe I didn't hit the first time, but
wasn't it me who suggested in "Comment from rigansen..." the use of the 'protected' keyword ??

0
 

Author Comment

by:sagitarian
ID: 1173491
I graded the answer with a "B" because that was my evaluation of the "answer". Only then I saw the comment. I think that the comment should have been the answer in the first place.
0

Featured Post

On Demand Webinar: Networking for the Cloud Era

Ready to improve network connectivity? Watch this webinar to learn how SD-WANs and a one-click instant connect tool can boost provisions, deployment, and management of your cloud connection.

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

  Included as part of the C++ Standard Template Library (STL) is a collection of generic containers. Each of these containers serves a different purpose and has different pros and cons. It is often difficult to decide which container to use and …
Go is an acronym of golang, is a programming language developed Google in 2007. Go is a new language that is mostly in the C family, with significant input from Pascal/Modula/Oberon family. Hence Go arisen as low-level language with fast compilation…
The goal of the video will be to teach the user the concept of local variables and scope. An example of a locally defined variable will be given as well as an explanation of what scope is in C++. The local variable and concept of scope will be relat…
The viewer will learn additional member functions of the vector class. Specifically, the capacity and swap member functions will be introduced.
Suggested Courses

771 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question