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Perl 5's glob() function

Posted on 1997-11-20
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Last Modified: 2006-11-17

I have just finished writing a script on my test machine making use of Perl 5's functionality and specifically, the GLOB function.

However, our production machine does not have Perl 5, but Perl 4 and therefore the code dependent upon the output of GLOB will not work.

Basically, the script itself will not work.

Is there an equivalent function to GLOB for Perl 4?  Or perhaps some code I could use to match this:

>
>@WorkingFiles = glob("$WorkingDir/$FileExt");
>
>open(LOG, '>>$LogFile');
>foreach $FileName (@WorkingFiles)

>

I'm working with files and filenames so the output of my script is dependent upon the data GLOB returns. :*(

It is very important that I am able to specify the files returned to me by wildcards (thus the usefulness of GLOB in this situation).

PLEASE ASSIST!!

JaTHaN
<o_/


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Question by:jathan
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Accepted Solution

by:
kistler earned 70 total points
ID: 1208815
@files = <$a/*>;
is the same as
@files = <$a/*>;
expect, that in the latter case "." and ".." may
show up as well.
But for perl4 <*> should work. If there is any problem,
you still have the "readdir" function.
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Expert Comment

by:kistler
ID: 1208816
I have tried another way around using the readdir like so:

opendir(WORKDIR, "$WorkingDir");

local(@WorkingFiles) = readdir(WORKDIR);
closedir(WORKDIR);

foreach $FileName (@WorkinDir) { ... }

The only problem with this approach is I have no way of specifying the extensions I want to work with.  Specifically, this script is table-driven and pulls the values for the strings $WorkingDir and $FileExt from said table.  

It is intended to perform a user-specified action (i.e, move, compress, delete) on files of extensions matching $FileExt in the directory $WorkingDir.  Does this help?

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