• C

Define pointers

How can I define three character pointers a, b, and c.
They are not arrays, and not initialized.
Make a point to "Hello", and b point to "World".
Concatenate these tow strings into c.
(Make sure c has enough memory allocated)
luonghtAsked:
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ozoCommented:
#include <string.h>
char *a,*b,*c;
a = "Hello";
b = "World";
c = (char *)malloc(strlen(a)+strlen(b)+1);
strcpy(c,a);
strcat(c,b);

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alexoCommented:
Ozo, that should have been an answer.
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messiahCommented:
The answer was a comment eh? :)

BTW, it's good programming practice to free up allocated memory after you're done with it :)

ie. free(c);

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ozoCommented:
And since you don't want to leave c pointing to unallocated memory:

c = 0;

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RONSLOWCommented:
Of course, in C, you don't need the (char*) cast - and it _can_ be dangerouse to leave it there.

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rbrCommented:
Ozo, pls Answer the question.
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ozoCommented:
/* Answer for rbr: */
#ifdef _SVID
#include <malloc.h>
#else
#include <stdlib.h>
#endif
#include <string.h>
#include <stdio.h>
char *a,*b,*c;
a = "Hello";
b = "World";
c = malloc(strlen(a)+1+strlen(b)+1);
sprintf(c,"%s %s",a,b);
/* we could free(c) here, but I'd prefer to wait till after it's been used */
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_ZaphodCommented:
Since the subject seems to be new to pointers, it might be prudent to add that you should _not_ try to modify *a or *b (including a[whatever] and b[whatever]) since that would be trying to modify parts of the executable in run-time, which will, in turn, cause a GPF or a segfault, depending on your operating system.
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ozoCommented:
It looks like luonght was less interested in geting this answered than rbr was.
luonght, if you don't like the answer, please reject it, if you do, please grade it.
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ozoCommented:
char *a,*b,*c;
a = strdup("Hello"); /* if you want *a to be modifiable */
b = strdup("World");
c = (char *)malloc(strlen(a)+strlen(b)+1);
strcpy(c,a);
strcat(c,b);
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